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A176205
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Coefficients of S(x) which satisfies S(x) = (1 + 3*x + 5*x^2)*S(x^2).
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1
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1, 3, 8, 9, 23, 24, 49, 27, 68, 69, 139, 72, 169, 147, 272, 81, 203, 204, 409, 207, 484, 417, 767, 216, 529, 507, 992, 441, 1007, 816, 1441, 243, 608, 609, 1219, 612, 1429, 1227, 2252, 621, 1519, 1452, 2837, 1251, 2852, 2301, 4051, 648, 1609, 1587, 3152, 1521, 3527, 2976, 5401, 1323, 3212, 3021, 5851, 2448
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OFFSET
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0,2
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COMMENTS
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Has an apparent fractal structure with the following properties:
a(n) for n = 0, 1, 3, 7, 15, ... are 1, 3, 9, 27, ....
Odd n-th terms are divisible by 3 (starting with n=1) creating the same sequence.
Then the result is relabeled with n=0,1,2,...; with the odds again divisible by 3, getting (1, 3, 8, 9, 23, ...); and so on.
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LINKS
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FORMULA
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Given M = an infinite triangular matrix with (1, 3, 5, ...) in each column; shifted down twice for columns > 0. Then A176205 = lim_{n->infinity} M^n, the left shifted vector considered as a sequence.
a(2*n) = a(n) + 5*a(n-1) and a(2*n+1) = 3*a(n), with a(0) = 1. - G. C. Greubel, Mar 13 2020
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MAPLE
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a:= proc(n) option remember;
if n=0 then 1
elif `mod`(n, 2)=0 then a(n/2) + 5*a(n/2 -1)
else 3*a((n-1)/2)
fi; end:
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MATHEMATICA
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a[n_]:= If[n==0, 1, If[EvenQ[n], a[n/2] +5*a[n/2 -1], 3*a[(n-1)/2]]]; Table[a[n], {n, 0, 60}] (* G. C. Greubel, Mar 13 2020 *)
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PROG
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(Sage)
@CachedFunction
def a(n):
if (n==0): return 1
elif (n%2==0): return a(n/2) + 5*a(n/2 -1)
else: return 3*a((n-1)/2)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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