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A124753
a(3n+k) = (k+1)*binomial(4n+k, n)/(3n+k+1), where k is n reduced mod 3.
11
1, 1, 1, 1, 2, 3, 4, 9, 15, 22, 52, 91, 140, 340, 612, 969, 2394, 4389, 7084, 17710, 32890, 53820, 135720, 254475, 420732, 1068012, 2017356, 3362260, 8579560, 16301164, 27343888, 70068713, 133767543, 225568798, 580034052, 1111731933, 1882933364, 4855986044, 9338434700
OFFSET
0,5
COMMENTS
Row sums of Riordan array (1,x(1-x^3))^(-1). Also row sums of A124752.
a(n) is the number of ordered trees (A000108) with n vertices in which every non-leaf non-root vertex has exactly two children that are leaves. For example, a(4) counts the 2 trees
\ /
| and \|/ . - David Callan, Aug 22 2014
Coefficients of the generating function E(1,t*E(4,t^3)) that appears on line 4 of Table 2 on page 210 of the Hering link. E(d,t)=1+t*E(d,t)^d is the generating function for Fuss-Catalan numbers. - Robert A. Russell, May 21 2026
LINKS
F. Hering, R. C. Read, and G. C. Shephard, The enumeration of stack polytopes and simplicial clusters, Discrete Math., 40 (1982), 203-217.
FORMULA
a(3n) = A002293(n), a(3n+1) = A069271(n), a(3n+2) = A006632(n+1).
a(n) = ((mod(n,3)+1)*C(4*floor(n/3)+mod(n,3), floor(n/3))/ (3*floor(n/3) + 1 + mod(n, 3))). - Paul Barry, Dec 14 2006
G.f. satisfies: A(x) = 1 + x*A(x)^2*A(w*x)*A(w^2*x), where w = exp(2*Pi*I/3). - Paul D. Hanna, Jun 04 2012
G.f. satisfies: A(x) = 1 + x*A(x)*G(x^3) where G(x) = 1 + x*G(x)^4 is the g.f. of A002293. - Paul D. Hanna, Jun 04 2012
Conjecture: +8019*n*(n-1)*(n+1)*a(n) +17496*n*(n-1)*(n-3)*a(n-1) +2592*(3*n-5)*(n-1)*(3*n-16)*a(n-2) +216*(-224*n^3+48*n^2+3926*n-6331)*a(n-3) +576*(-288*n^3+2448*n^2-6558*n+5443)*a(n-4) +768*(-288*n^3+3600*n^2-14878*n+20375)*a(n-5) -8192*(4*n-23)*(2*n-11)*(4*n-21)*a(n-6)=0. - R. J. Mathar, Oct 30 2014
a(0) = 1; a(n) = Sum_{k=0..floor((n-1)/3)} a(3*k) * a(n-1-3*k). - Seiichi Manyama, Jul 07 2025
MAPLE
A124753 := proc(n)
local k, np;
k := modp(n, 3) ;
np := floor(n/3) ;
(k+1)*binomial(np+n, np)/(n+1) ;
end proc:
seq(A124753(n), n=0..40) ; # R. J. Mathar, Oct 30 2014
MATHEMATICA
a[n_] := Module[{q, k}, {q, k} = QuotientRemainder[n, 3]; (k+1)*Binomial[4q + k, q]/(3q + k + 1)];
Table[a[n], {n, 0, 34}] (* Jean-François Alcover, Nov 20 2017 *)
PROG
(PARI) {a(n)=local(A=1+x); for(i=1, n, A=1+x*A*exp(sum(m=1, n\3, 3*polcoeff(log(A+x*O(x^n)), 3*m)*x^(3*m))+x*O(x^n))); polcoeff(A, n)} \\ Paul D. Hanna, Jun 04 2012
(PARI) apr(n, p, r) = r*binomial(n*p+r, n)/(n*p+r);
a(n) = apr(n\3, 4, n%3+1); \\ Seiichi Manyama, Jul 20 2025
CROSSREFS
Cf. A084080, A002293, A069271 (trisection), A006632 (trisection).
Sequence in context: A033076 A121431 A084080 * A248647 A284437 A049909
KEYWORD
nonn,easy
AUTHOR
Paul Barry, Nov 06 2006
STATUS
approved