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A047749
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If n = 2*m then a(n) = binomial(3*m, m)/(2*m+1), if n=2*m+1 then a(n) = binomial(3*m+1, m+1)/(2*m+1).
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40
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1, 1, 1, 2, 3, 7, 12, 30, 55, 143, 273, 728, 1428, 3876, 7752, 21318, 43263, 120175, 246675, 690690, 1430715, 4032015, 8414640, 23841480, 50067108, 142498692, 300830572, 859515920, 1822766520, 5225264024, 11124755664, 31983672534
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OFFSET
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0,4
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COMMENTS
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Hankel transform appears to be a signed aerated version of A059492. - Paul Barry, Apr 16 2008
Row sums of inverse Riordan array (1, x*(1-x^2))^(-1). - Paul Barry, Apr 16 2008
a(n) is the number of permutations of length n avoiding 213 in the classical sense which are breadth-first search reading words of increasing unary-binary trees. For more details, see the entry for permutations avoiding 231 at A245898. - Manda Riehl, Aug 05 2014
a(n) is the number of ordered trees (A000108) with n vertices in which every non-root non-leaf vertex has exactly one leaf child (no restriction on its non-leaf children). For example, a(4) counts the 3 trees
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(End)
a(n) is the number of symmetric ternary trees having n internal nodes.
a(n) is the number of symmetric non-crossing rooted trees having n edges.
a(n) is the number of symmetric even trees having 2n edges.
a(n) is the number of symmetric diagonally convex directed polyominoes having n diagonals.
(End)
For the above 4 items see the Deutsch-Feretic-Noy reference.
a(n) is also the number of self-dual labeled non-crossing trees with n edges. See my paper in the links section. - Nikos Apostolakis, Jun 11 2019
Number of achiral polyominoes composed of n square cells of the hyperbolic regular tiling with Schläfli symbol {4,oo}. A stereographic projection of this tiling on the Poincaré disk can be obtained via the Christensson link. An achiral polyomino is identical to its reflection. - Robert A. Russell, Jan 20 2024
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LINKS
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FORMULA
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G.f. is 1+Z, where Z satisfies x*Z^3 + (3*x-2)*Z^2 + (3*x-1)*Z + x = 0. Equivalently, the g.f. Y satisfies x*Y^3 - 2*Y^2 + 3*Y - 1 = 0. - Vladeta Jovovic, Dec 06 2002
Reversion of g.f. (x-2*x^2)/(1-x)^3 (ignoring signs). - Ralf Stephan, Mar 22 2004
G.f.: (4/(3*x))*(sin((1/3)*asin(sqrt(27*x^2/4))))^2 +(2/sqrt(3*x^2))*sin((1/3)*asin(sqrt(27*x^2/4))). - Paul Barry, Nov 08 2006
G.f.: 1/(1-2*sin(asin(3*sqrt(3)*x/2)/3)/sqrt(3)). - Paul Barry, Apr 16 2008
G.f. satisfies: A(x) = 1 + x*A(x)^2*A(-x);
also, A(x)*A(-x) = B(x^2) where B(x) = 1 + x*B(x)^3 = g.f. of A001764.
(End)
G.f.: 1/(1-C(x)) where C(x) = Reverse(x-x^3) = x + x^3 + 3*x^5 + 12*x^7 + 55*x^9 + ... (cf. A001764). - Joerg Arndt, Apr 16 2011
G.f.: G(z^2)+z*G(z^2)^2, where G(z) = 1 + z*G(z)^3, the generating function for A001764. - Robert A. Russell, Jan 26 2024
a(n) is the upper left term in M^n, M = the infinite square production matrix:
1, 1, 0, 0, 0, 0, ...
0, 0, 1, 0, 0, 0, ...
1, 1, 0, 1, 0, 0, ...
0, 0, 1, 0, 1, 0, ...
1, 1, 0, 1, 0, 1, ...
... (End)
Conjecture D-finite with recurrence: 8*n*(n+1)*a(n) + 36*n*(n-2)*a(n-1) - 6*(9*n^2-18*n+14)*a(n-2) - 27*(3*n-7)*(3*n-8)*a(n-3) = 0. - R. J. Mathar, Dec 19 2011
0 = a(n)*(+7308954*a(n+2) - 16659999*a(n+3) - 4854519*a(n+4) + 6201838*a(n+5)) + a(n+1)*(-406053*a(n+2) - 1627560*a(n+3) + 1683538*a(n+4) - 245747*a(n+5)) + a(n+2)*(+45117*a(n+2) + 235870*a(n+3) + 173953*a(n+4) - 484295*a(n+5)) + a(n+3)*(-41820*a(n+3) - 50184*a(n+4) + 22304*a(n+5)) for all n in Z if a(-1) = -2/3. - Michael Somos, Oct 29 2014
a(0) = 1; a(n) = Sum_{i=0..n-1} Sum_{j=0..n-i-1} (-1)^i * a(i) * a(j) * a(n-i-j-1). - Ilya Gutkovskiy, Jul 28 2021
a(n) = U(n) in the Beineke and Pippert link.
G.f.: E(1)(t*E(3)(t^2)) (second entry in Table 1), where E(d)(t) is defined in formula 3 of Hering link. (End)
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EXAMPLE
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G.f. = 1 + x + x^2 + 2*x^3 + 3*x^4 + 7*x^5 + 12*x^6 + 30*x^7 + 55*x^8 + ...
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MAPLE
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A047749 := proc(m) if m mod 2 = 1 then x := (m-1)/2; RETURN((3*x+1)!/((x+1)!*(2*x+1)!)); fi; x := m/2; RETURN((3*x)!/(x!*(2*x+1)!)); end;
A047749 := proc(m) local x; if m mod 2 = 1 then x := (m-1)/2; RETURN((3*x+1)!/((x+1)!*(2*x+1)!)); fi; RETURN(A001764(m/2)); end;
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MATHEMATICA
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a[ n_] := If[ n < 1, Boole[n == 0], SeriesCoefficient[ InverseSeries[ Series[ (x + 2 x^2) / (1 + x)^3, {x, 0, n}]], {x, 0, n}]]; (* Michael Somos, Oct 29 2014 *)
Table[If[OddQ[n], 2Binomial[(3n-1)/2, (n-1)/2], Binomial[3n/2, n/2]]/(n+1), {n, 0, 40}] (* Robert A. Russell, Jan 19 2024 *)
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PROG
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(PARI) {a(n)=local(A=1+x); for(i=1, n, A=1+x*A^2*subst(A, x, -x+x*O(x^n))); polcoeff(A, n)} \\ Paul D. Hanna, Sep 20 2009
(PARI) x='x+O('x^66);
C(x)=serreverse(x-x^3); /* =x+x^3+3*x^5+12*x^7+55*x^9 +..., cf. A001764 */
s=1/(1-C(x)); /* g.f. */
(Sage)
D = [0]*n; D[1] = 1
R = []; b = False; h = 1
for i in range(n) :
for k in (1..h) :
D[k] = D[k] + D[k-1]
R.append(D[h])
if b : h += 1
b = not b
return R
(Sage) [1]+[((1+(-1)^n)*binomial(3*n/2, n/2)/(n+1) + (1-(-1)^n)* binomial((3*n-1)/2, (n+1)/2)/n)/2 for n in (1..35)] # G. C. Greubel, Jul 07 2019
(Magma) G:=Gamma; [Round((1+(-1)^n)*G(3*n/2+1)/(G(n/2+1)*Factorial(n+1)) + (1-(-1)^n)*G((3*n+1)/2)/(G((n+3)/2)*Factorial(n)))/2: n in [0..35]]; // G. C. Greubel, Jul 07 2019
(Python)
from math import comb
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CROSSREFS
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Cf. A006013 is the odd-indexed terms of this sequence.
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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