A110486 Indices of Fibonacci numbers in A068136(n); that is, a(n) = least k such that the digits of Fibonacci(k) begin with the concatenation 1234..n.

1, 26, 227, 1629, 49517, 125488, 125488

Offset

1,2

Comments

The sequence is strictly nondecreasing. Next term, if it exists, is greater than 1,800,000.

Links

Table of n, a(n) for n=1..7.

Example

fibonacci(227) = 123227981463641240980692501505442003148737643593 is the least Fibonacci number beginning with the concatenation 123, so a(3) = 227.

Mathematica

k = 1; Do[l = IntegerDigits[Fibonacci[n]]; While[Take[l, Min[Length[l], k]] == Range[1, k], Print[n]; k++ ], {n, 1, 1800000}]

Crossrefs

Cf. A068136 (corresponding Fibonacci numbers).

Sequence in context: A269658 A220714 A159519 * A098994 A172124 A196633

Adjacent sequences: A110483 A110484 A110485 * A110487 A110488 A110489

Keyword

base,hard,nonn

Author

Ryan Propper, Sep 10 2005

Status

approved