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A110488
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A number triangle based on the Catalan numbers.
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3
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1, 1, 1, 2, 2, 1, 5, 5, 3, 1, 14, 14, 10, 4, 1, 42, 42, 35, 17, 5, 1, 132, 132, 126, 74, 26, 6, 1, 429, 429, 462, 326, 137, 37, 7, 1, 1430, 1430, 1716, 1446, 726, 230, 50, 8, 1, 4862, 4862, 6435, 6441, 3858, 1434, 359, 65, 9, 1, 16796, 16796, 24310, 28770, 20532, 8952, 2582, 530, 82, 10, 1
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graph;
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OFFSET
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0,4
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COMMENTS
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LINKS
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FORMULA
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T(n, k) = Sum_{j=0..(n-k)} 2*(j+1)*(k-1)^j*C(2(n-k)+1, n-k-j)/(n-k+j+2)}.
Column k has g.f. x^k*c(x)/(1-k*x*c(x)) where c(x) is the g.f. of A000108.
T(n,0) = Catalan(n), T(n,1) = Catalan(n), T(n,n) = 1. - G. C. Greubel, Aug 28 2017
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EXAMPLE
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Rows begin
1;
1, 1;
2, 2, 1;
5, 5, 3, 1;
14, 14, 10, 4, 1;
42, 42, 35, 17, 5, 1;
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MATHEMATICA
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T[n_, 0] := CatalanNumber[n]; T[n_, 1] := CatalanNumber[n]; T[n_, n_] := 1; T[n_, k_] := Sum[2*(j + 1)*(k - 1)^j*Binomial[2 (n - k) + 1, n - k - j]/(n - k + j + 2), {j, 0, n - k}]; Table[T[n, k], {n, 0, 10}, {k, 0, n}] // Flatten (* G. C. Greubel, Aug 28 2017 *)
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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