|
|
A097464
|
|
5-infinitary perfect numbers: n such that 5-infinitary-sigma(n)=2*n.
|
|
3
|
|
|
|
OFFSET
|
1,1
|
|
COMMENTS
|
Here 5-infinitary-sigma(a) means sum of 5-infinitary-divisor of a. If n=Product p_i^r_i and d=Product p_i^s_i, each s_i has a digit a<=b in its 5-ary expansion everywhere that the corresponding r_i has a digit b, then d is a 5-infinitary-divisor of n.
Is it certain that 308474880 is the 6th term? M. F. Hasler, Nov 20 2010
|
|
LINKS
|
|
|
FORMULA
|
|
|
EXAMPLE
|
Factorizations: 2*3, 2^2*7, 2^4*31, 2^5*3^3*5*11, 2^5*3^2*7*11*13, 2^10*3*5*7*19*151
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
|
|
EXTENSIONS
|
|
|
STATUS
|
approved
|
|
|
|