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 A093005 a(n) = n * ceiling(n/2). 27
 1, 2, 6, 8, 15, 18, 28, 32, 45, 50, 66, 72, 91, 98, 120, 128, 153, 162, 190, 200, 231, 242, 276, 288, 325, 338, 378, 392, 435, 450, 496, 512, 561, 578, 630, 648, 703, 722, 780, 800, 861, 882, 946, 968, 1035, 1058, 1128, 1152, 1225, 1250, 1326, 1352, 1431, 1458 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,2 COMMENTS Old name was: The lone multiple of n among the next n numbers. Another old name: a(n) = n*floor((n+1)/2). Consider the triangle 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 ... Then sequence contains the multiple of n in the n-th row. Interleaves A000384 and A001105. - Paul Barry, Jun 29 2006 Termwise products of the natural numbers and the natural numbers repeated. Number of pairs (x,y) having the same parity, with x in {0,...,n} and y in {0,...,2n}. - Clark Kimberling, Jul 02 2012 Similar to generalized hexagonal numbers A000217. Other members of this family are A210977, A006578, A210978, A181995, A210981, A210982. - Omar E. Pol, Aug 09 2012 For even n, a(n) gives the sum of all the parts in the partitions of n into exactly two parts. For odd n>1, a(n) gives n plus the sum of all the parts in the partitions of n into exactly two parts. - Wesley Ivan Hurt, Nov 14 2013 Number of regions of the plane that do not contain the origin, in the arrangement of lines with polar equations rho = 1/cos(theta-k*2*Pi/n), k=0..n-1; or, by inversion, number of bounded regions in the arrangement of circles with radius 1 and centers the n-th roots of unity. - Luc Rousseau, Feb 08 2019 Numbers k such that floor(sqrt(2k)+1/2) | k. - Wesley Ivan Hurt, Dec 01 2020 LINKS Harvey P. Dale, Table of n, a(n) for n = 1..1000 Torleiv Kløve, Linear recurring sequences in boolean rings, Math. Scand., 33 (1973), 5-12. Torleiv Kløve, Linear recurring sequences in boolean rings, Math. Scand., 33 (1973), 5-12. (Annotated scanned copy) Luc Rousseau, Illustration, a(n) viewed as a number of regions in an arrangement of lines / of circles. Index entries for linear recurrences with constant coefficients, signature (1,2,-2,-1,1). FORMULA a(n) = n*floor((n+1)/2). a(n) = n*A008619(n). a(2*n-1) = n*(2*n-1), a(2*n) = 2*n^2. From Paul Barry, Jun 29 2006: (Start) G.f.: x*(1+x+2*x^2)/((1+x)^2*(1-x)^3). a(n) = a(n-1) + 2*a(n-2) - 2*a(n-3) - a(n-4) + a(n-5). a(n) = n*((2*n+1) - (-1)^n)/4. (End) a(n) = n * ceiling(n/2). - Wesley Ivan Hurt, Nov 14 2013 E.g.f.: (1/2)*x*( (x+2)*cosh(x) + (x+1)*sinh(x) ). - G. C. Greubel, Mar 14 2024 Sum_{n>=1} 1/a(n) = Pi^2/12 + 2*log(2). - Amiram Eldar, Mar 15 2024 MAPLE A093005:=n->n*ceil(n/2); seq(A093005(n), n=1..100); # Wesley Ivan Hurt, Nov 14 2013 MATHEMATICA a[n_Integer] := n*Floor[(n + 1)/2] (* Olivier Gérard, Jun 21 2007 *) Table[n*Ceiling[n/2], {n, 60}] (* or *) LinearRecurrence[{1, 2, -2, -1, 1}, {1, 2, 6, 8, 15}, 60] (* Harvey P. Dale, May 08 2014 *) PROG (Python) for n in range(1, 55): print(n*((n+1)//2), end=", ") # Alex Ratushnyak, Apr 26 2012 (PARI) a(n)=(n+1)\2*n \\ Charles R Greathouse IV, Jun 11 2015 (Magma) [n*(n+(n mod 2))/2: n in [1..70]]; // G. C. Greubel, Mar 14 2024 (SageMath) [n*(n +(n%2))/2 for n in range(1, 71)] # G. C. Greubel, Mar 14 2024 CROSSREFS Cf. A000217, A000384, A001105, A006578, A008619 (a(n)/n), A181995. Cf. A183207, A210977, A210978, A210981, A210982. Sequence in context: A228366 A345958 A128913 * A049818 A066189 A278834 Adjacent sequences: A093002 A093003 A093004 * A093006 A093007 A093008 KEYWORD nonn,easy AUTHOR Amarnath Murthy, Mar 29 2004 EXTENSIONS Corrected and extended by Joshua Zucker, May 08 2006 New name from Alex Ratushnyak, Apr 26 2012 New name from Wesley Ivan Hurt, Nov 14 2013 STATUS approved

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Last modified May 30 15:08 EDT 2024. Contains 372968 sequences. (Running on oeis4.)