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A088528
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Let m = number of ways of partitioning n into parts using all the parts of a subset of {1, 2, ..., n-1} whose sum of all parts of a subset is less than n; a(n) gives number of different subsets of {1, 2, ..., n-1} whose m is 0.
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12
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0, 0, 1, 1, 3, 3, 6, 6, 10, 12, 17, 18, 26, 30, 40, 44, 58, 66, 84, 95, 120, 135, 166, 186, 230, 257, 314, 350, 421, 476, 561, 626, 749, 831, 986, 1095, 1276, 1424, 1666, 1849, 2138, 2388, 2741, 3042, 3522, 3879, 4441, 4928, 5617, 6222, 7084, 7802, 8852, 9800
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OFFSET
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1,5
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COMMENTS
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Note that {2, 3} is counted for n = 6 because although 6 = 2+2+2 = 3+3, there is no partition that includes both 2 and 3. - David Wasserman, Aug 09 2005
Said differently, a(n) is the number of finite nonempty sets of positive integers with sum < n that cannot be linearly combined using all positive coefficients to obtain n. - Gus Wiseman, Sep 10 2023
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LINKS
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EXAMPLE
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a(5)=3 because there are three different subsets, {2}, {3} & {4}; a(6)=3 because there are three different subsets, {4}, {5} & {2,3}.
The set {3,5} is not counted under a(8) because 1*3 + 1*5 = 8, but it is counted under a(9) and a(10), and it is not counted under a(11) because 2*3 + 1*5 = 11.
The a(3) = 1 through a(11) = 17 subsets:
{2} {3} {2} {4} {2} {3} {2} {3} {2}
{3} {5} {3} {5} {4} {4} {3}
{4} {2,3} {4} {6} {5} {6} {4}
{5} {7} {6} {7} {5}
{6} {2,5} {7} {8} {6}
{2,4} {3,4} {8} {9} {7}
{2,4} {2,5} {8}
{2,6} {2,7} {9}
{3,4} {3,5} {10}
{3,5} {3,6} {2,4}
{4,5} {2,6}
{2,3,4} {2,8}
{3,6}
{3,7}
{4,5}
{4,6}
{2,3,5}
(End)
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MATHEMATICA
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combp[n_, y_]:=With[{s=Table[{k, i}, {k, y}, {i, 1, Floor[n/k]}]}, Select[Tuples[s], Total[Times@@@#]==n&]];
Table[Length[Select[Select[Subsets[Range[n]], 0<Total[#]<n&], combp[n, #]=={}&]], {n, 15}] (* Gus Wiseman, Sep 12 2023 *)
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CROSSREFS
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For sets with max < n instead of sum < n we have A365045, nonempty A070880.
For sets with max <= n we have A365322.
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KEYWORD
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easy,nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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