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A053700
a(n) = 111111 in base n.
14
6, 63, 364, 1365, 3906, 9331, 19608, 37449, 66430, 111111, 177156, 271453, 402234, 579195, 813616, 1118481, 1508598, 2000719, 2613660, 3368421, 4288306, 5399043, 6728904, 8308825, 10172526, 12356631, 14900788, 17847789, 21243690, 25137931
OFFSET
1,1
LINKS
Carlos M. da Fonseca and Anthony G. Shannon, A formal operator involving Fermatian numbers, Notes Num. Theor. Disc. Math. (2024) Vol. 30, No. 3, 491-498.
FORMULA
a(n) = n^5 + n^4 + n^3 + n^2 + n + 1 = (n^6-1)/(n-1).
G.f.: x*(6 + 27*x + 76*x^2 + 6*x^3 + 6*x^4 - x^5)/(1-x)^6. - Colin Barker, May 08 2012
E.g.f.: exp(x)*(1 + 5*x + 26*x^2 + 32*x^3 + 11*x^4+ x^5) - 1. - Stefano Spezia, Oct 03 2024
EXAMPLE
a(3)=364 because 111111 base 3 = 243 + 81 + 27 + 9 + 3 + 1 = 121.
MATHEMATICA
Table[(n^5+n^4+n^3+n^2+n+1), {n, 0, 5!}] (* Vladimir Joseph Stephan Orlovsky, Mar 06 2010 *)
PROG
(PARI) a(n)=(n^6-1)/(n-1) \\ Charles R Greathouse IV, Sep 28 2015
CROSSREFS
6th row of the array A055129.
Cf. A104878.
Sequence in context: A027811 A027950 A184447 * A296393 A123615 A245754
KEYWORD
base,nonn,easy
AUTHOR
Henry Bottomley, Mar 23 2000
STATUS
approved