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A035615
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Number of winning length n strings with a 2-symbol alphabet in "same game".
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20
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1, 0, 2, 2, 6, 12, 26, 58, 126, 278, 602, 1300, 2774, 5878, 12350, 25778, 53470, 110332, 226610, 463602, 945214, 1921550, 3896642, 7885092, 15927086, 32121582, 64697726, 130166378, 261637446, 525478668, 1054673162, 2115601450, 4241716734, 8501080838, 17031744170
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OFFSET
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0,3
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COMMENTS
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Strings that can be reduced to null string by repeatedly removing an entire run of two or more consecutive symbols.
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LINKS
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Sascha Kurz, Polynomials for same game, pdf.
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FORMULA
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G.f.: x(2x^6 - 6x^5 + 8x^4 + 2x^3 - 6x^2 + 2x)/[(1 - x^2)(1 - 2x)(1 - x - x^2)^2] (conjectured). - Ralf Stephan, May 11 2004. Established by Burns and Purcell - see link.
a(0) = 1, a(1) = 0, a(2) = 2, a(3) = 2, a(4) = 6, a(5) = 12, a(6) = 26, a(7) = 58, a(n) = 4*a(n-1) - 2*a(n-2) - 8*a(n-3) + 6*a(n-4) + 6*a(n-5) - 3*a(n-6) - 2*a(n-7). - Harvey P. Dale, Sep 26 2012
a(n) = 2^n - 2 * n * Fibonacci(n-2) - (-1)^n - 1 for n >= 2 (proved by Burns and Purcell (2005, 2007)). - Petros Hadjicostas, Jul 04 2018
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EXAMPLE
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11011001 is a winning string since 110{11}001 -> 11{000}1 -> {111} -> null.
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MATHEMATICA
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Join[{1}, Rest[CoefficientList[Series[x (2x^6 - 6x^5 + 8x^4 + 2x^3 - 6x^2 + 2x)/((1 - x^2)(1 - 2x)(1 - x - x^2)^2), {x, 0, 40}], x]]] (* or *) Join[{1}, LinearRecurrence[{4, -2, -8, 6, 6, -3, -2}, {0, 2, 2, 6, 12, 26, 58}, 40]] (* Harvey P. Dale, Sep 26 2012 *)
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PROG
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(PARI) a(n)=if(n, ([0, 1, 0, 0, 0, 0, 0; 0, 0, 1, 0, 0, 0, 0; 0, 0, 0, 1, 0, 0, 0; 0, 0, 0, 0, 1, 0, 0; 0, 0, 0, 0, 0, 1, 0; 0, 0, 0, 0, 0, 0, 1; -2, -3, 6, 6, -8, -2, 4]^(n-1)*[0; 2; 2; 6; 12; 26; 58])[1, 1], 1) \\ Charles R Greathouse IV, Jun 15 2015
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CROSSREFS
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See A309874 for the losing strings.
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KEYWORD
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nonn,nice,easy
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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