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A032446
Number of solutions to phi(k) = 2n.
11
3, 4, 4, 5, 2, 6, 0, 6, 4, 5, 2, 10, 0, 2, 2, 7, 0, 8, 0, 9, 4, 3, 2, 11, 0, 2, 2, 3, 2, 9, 0, 8, 2, 0, 2, 17, 0, 0, 2, 10, 2, 6, 0, 6, 0, 3, 0, 17, 0, 4, 2, 3, 2, 9, 2, 6, 0, 3, 0, 17, 0, 0, 2, 9, 2, 7, 0, 2, 2, 3, 0, 21, 0, 2, 2, 0, 0, 7, 0, 12, 4, 3, 2, 12, 0, 2, 0, 8, 2, 10
OFFSET
1,1
COMMENTS
By Carmichael's conjecture, a(n) <> 1 for any n. See A074987. - Thomas Ordowski, Sep 13 2017
a(n) = 0 iff n is a term of A079695. - Bernard Schott, Oct 02 2021
REFERENCES
Albert H. Beiler, Recreations in the Theory of Numbers, The Queen of Mathematics Entertains, Second Edition, Dover Publications, Inc., NY, 1966, page 90.
LINKS
Matteo Caorsi and Sergio Cecotti, Geometric classification of 4d N=2 SCFTs, arXiv:1801.04542 [hep-th], 2018.
Carl Pomerance, Popular values of Euler's function, Mathematica 27 (1980), 84-89.
EXAMPLE
If n = 8 then phi(x) = 2*8 = 16 is satisfied for only a(8) = 6 values of x, viz. 17, 32, 34, 40, 48, 60.
MAPLE
with(numtheory); [ seq(nops(invphi(2*n)), n=1..90) ];
MATHEMATICA
t = Table[0, {100} ]; Do[a = EulerPhi[n]; If[a < 202, t[[a/2]]++ ], {n, 3, 10^5} ]; t
PROG
(Magma) [#EulerPhiInverse( 2*n):n in [1..100]]; // Marius A. Burtea, Sep 08 2019
(PARI) a(n) = invphiNum(2*n); \\ Amiram Eldar, Nov 15 2024 using Max Alekseyev's invphi.gp
CROSSREFS
Bisection of A014197.
Cf. A006511 (largest k for which A000010(k) = A002202(n)), A057635.
Sequence in context: A185271 A352285 A158012 * A271563 A342938 A028949
KEYWORD
nonn,easy,nice,changed
AUTHOR
Ursula Gagelmann (gagelmann(AT)altavista.net)
EXTENSIONS
Extended by Robin Trew (trew(AT)hcs.harvard.edu).
STATUS
approved