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A008845
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Numbers k such that k+1 and k/2+1 are squares.
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1
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0, 48, 1680, 57120, 1940448, 65918160, 2239277040, 76069501248, 2584123765440, 87784138523760, 2982076586042448, 101302819786919520, 3441313796169221280, 116903366249966604048, 3971273138702695316400, 134906383349641674153600, 4582845760749114225906048
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OFFSET
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0,2
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REFERENCES
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A. H. Beiler, Recreations in the Theory of Numbers, Dover, NY, 1964, p. 256.
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LINKS
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FORMULA
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a(0)=0, a(1)=48, a(2)=1680, a(n) = 35*a(n-1) - 35*a(n-2) + a(n-3). - Harvey P. Dale, May 24 2014
a(n) = (-6+(3-2*sqrt(2))*(17+12*sqrt(2))^(-n)+(3+2*sqrt(2))*(17+12*sqrt(2))^n)/4.
G.f.: 48*x / ((1-x)*(1-34*x+x^2)).
(End)
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EXAMPLE
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48+1 = 49 = 7^2 and 48/2+1 = 24+1 = 25 = 5^2.
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MAPLE
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seq(coeff(series(48*x/((1-x)*(1-34*x+x^2)), x, n+1), x, n), n = 0..20); # G. C. Greubel, Sep 13 2019
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MATHEMATICA
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LinearRecurrence[{35, -35, 1}, {0, 48, 1680}, 20] (* Harvey P. Dale, May 24 2014 *)
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PROG
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(PARI) concat(0, Vec(48*x/((1-x)*(1-34*x+x^2)) + O(x^20))) \\ Colin Barker, Mar 02 2016
(Magma) I:=[0, 48]; [n le 2 select I[n] else 34*Self(n-1) - Self(n-2)+48: n in [1..20]]; // Vincenzo Librandi, Mar 03 2016
(Sage)
P.<x> = PowerSeriesRing(ZZ, prec)
return P(48*x/((1-x)*(1-34*x+x^2))).list()
(GAP) a:=[0, 48, 1680];; for n in [4..20] do a[n]:=35*a[n-1]-35*a[n-2] +a[n-3]; od; a; # G. C. Greubel, Sep 13 2019
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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