

A176542


Numbers n such that there are only a finite nonzero number of sets of n consecutive triangular numbers that sum to a square.


9



32, 50, 98, 128, 200, 242, 338, 392, 512, 578, 722, 800, 968, 1058, 1250, 1352, 1568, 1682, 1922, 2048, 2312, 2450, 2738, 2888, 3200, 3362, 3698, 3872, 4232, 4418, 4802, 5000, 5408, 5618, 6050, 6272, 6728, 6962, 7442, 7688, 8192, 8450, 8978, 9248, 9800
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OFFSET

1,1


COMMENTS

Members of A176541, for which there are only a finite number of solutions.
Integer n is in this sequence if n=2*m^2 and the equation (2*xm*y)*(2*x+m*y)=A077415(n)/2 has integer solutions with y>=n.  Max Alekseyev, May 10 2010
It seems that a(n) = 2*A001651(n+2)^2.  Colin Barker, Sep 25 2015


LINKS

Table of n, a(n) for n=1..45.


FORMULA

Conjectures from Colin Barker, Sep 24 2015: (Start)
a(n) = (9*n^2+24*n+16)/2 for n even.
a(n) = (9*n^2+30*n+25)/2 for n odd.
a(n) = a(n1)+2*a(n2)2*a(n3)a(n4)+a(n5) for n>5.
G.f.: 2*x*(4*x^43*x^38*x^2+9*x+16) / ((x1)^3*(x+1)^2).
(End)


EXAMPLE

32 is in this sequence because there is only one set of 32 consecutive triangular numbers that sum to a square (namely, A000217(26) thru A000217(57), which sum to 29584 = 172^2).
3 is NOT in this sequence, because there are infinitely many sets of 3 consecutive triangular numbers that sum to a square (cf. A165517).
4 is NOT in this sequence, because there are infinitely many sets of 4 consecutive triangular numbers that sum to a square (cf. A202391).
5 is NOT is this sequence, because there are NO sets of 5 consecutive triangular numbers that sum to a square.
11 is NOT in this sequence, since there are infinitely many sets of 11 consecutive triangular numbers that sum to a square (cf. A116476).


CROSSREFS

Cf. A176541, A000217, A000292, A077415.
Sequence in context: A037008 A316943 A099048 * A346917 A343154 A048734
Adjacent sequences: A176539 A176540 A176541 * A176543 A176544 A176545


KEYWORD

nonn


AUTHOR

Andrew Weimholt, Apr 20 2010


EXTENSIONS

Terms a(6) onward from Max Alekseyev, May 10 2010


STATUS

approved



