A010887 Simple periodic sequence: repeat 1,2,3,4,5,6,7,8.

1, 2, 3, 4, 5, 6, 7, 8, 1, 2, 3, 4, 5, 6, 7, 8, 1, 2, 3, 4, 5, 6, 7, 8, 1, 2, 3, 4, 5, 6, 7, 8, 1, 2, 3, 4, 5, 6, 7, 8, 1, 2, 3, 4, 5, 6, 7, 8, 1, 2, 3, 4, 5, 6, 7, 8, 1, 2, 3, 4, 5, 6, 7, 8, 1, 2, 3, 4, 5, 6, 7, 8, 1, 2, 3, 4, 5, 6, 7, 8, 1

Offset

0,2

Comments

Partial sums are given by A130486(n)+n+1. - Hieronymus Fischer, Jun 08 2007

1371742/11111111 = 0.123456781234567812345678... - Eric Desbiaux, Nov 03 2008

Links

Table of n, a(n) for n=0..80.

Index entries for linear recurrences with constant coefficients, signature (0,0,0,0,0,0,0,1).

Formula

a(n) = 1 + (n mod 8) - Paolo P. Lava, Nov 21 2006

From Hieronymus Fischer, Jun 08 2007: (Start)

a(n) = (1/2)*(9 - (-1)^n - 2*(-1)^(b/4) - 4*(-1)^((b - 2 + 2*(-1)^(b/4))/8)) where b = 2n - 1 + (-1)^n.

Also a(n) = A010877(n) + 1.

G.f.: g(x) = (1/(1-x^8))*Sum_{k=0..7} (k+1)*x^k.

Also: g(x) = (8x^9 - 9x^8 + 1)/((1-x^8)*(1-x)^2). (End)

Mathematica

PadRight[{}, 90, Range[8]] (* Harvey P. Dale, May 10 2022 *)

Prog

(Haskell)
a010887 = (+ 1) . flip mod 8
a010887_list = cycle [1..8]
-- Reinhard Zumkeller, Nov 09 2014, Mar 04 2014
(Python)
def A010887(n): return 1 + (n & 7) # Chai Wah Wu, May 25 2022

Crossrefs

Cf. A010872, A010873, A010874, A010875, A010876, A010878, A004526, A002264, A002265, A002266.

Cf. A177034 (decimal expansion of (9280+3*sqrt(13493990))/14165). - Klaus Brockhaus, May 01 2010

Sequence in context: A190598 A338882 A053844 * A101412 A338496 A053830

Adjacent sequences: A010884 A010885 A010886 * A010888 A010889 A010890

Keyword

nonn,easy

Author

N. J. A. Sloane

Status

approved