

A006318


Large Schroeder numbers.
(Formerly M1659)


171



1, 2, 6, 22, 90, 394, 1806, 8558, 41586, 206098, 1037718, 5293446, 27297738, 142078746, 745387038, 3937603038, 20927156706, 111818026018, 600318853926, 3236724317174, 17518619320890, 95149655201962, 518431875418926
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OFFSET

0,2


COMMENTS

The number of perfect matchings in a triangular grid of n squares (n = 1, 4, 9, 16, 25, ...).  Roberto E. Martinez II, Nov 05 2001
a(n) is the number of subdiagonal paths from (0, 0) to (n, n) consisting of steps East (1, 0), North (0, 1) and Northeast (1, 1) (sometimes called royal paths).  David Callan, Mar 14 2004
Twice A001003 (except for the first term).
a(n) is the number of dissections of a regular (n+4)gon by diagonals that do not touch the base. (A diagonal is a straight line joining two nonconsecutive vertices and dissection means the diagonals are noncrossing though they may share an endpoint. One side of the (n+4)gon is designated the base.) Example: a(1)=2 because a pentagon has only 2 such dissections: the empty one and the one with a diagonal parallel to the base.  David Callan, Aug 02 2004
From Jonathan Vos Post, Dec 23 2004: (Start)
The only prime in this sequence is 2. The semiprimes (intersection with A001358) are a(2) = 6, a(3) = 22, a(4) = 394, a(9) = 206098 and a(215), and correspond 1to1 with prime superCatalan numbers, also called prime little Schroeder numbers (intersection of A001003 and A000040), which are listed as A092840 and indexed as A092839.
The 3almost prime large Schroeder numbers a(7) = 8558, a(11) = 5293446, a(17) = 111818026018, a(19) = 3236724317174, a(21) = 95149655201962 (intersection of A006318 and A014612) correspond 1to1 with semiprime superCatalan numbers, also called semiprime little Schroeder numbers (intersection of A001003 and A001358), which are listed as A101619 and indexed as A101618. These relationships all derive from the fact that a(n) = 2*A001003(n).
Eric W. Weisstein comments that the Schroeder numbers bear the same relationship to the Delannoy numbers (A001850) as the Catalan numbers (A000108) do to the binomial coefficients. (End)
a(n) is the number of lattice paths from (0, 0) to (n+1, n+1) consisting of unit steps north N = (0, 1) and variablelength steps east E = (k, 0), with k a positive integer, that stay strictly below the line y = x except at the endpoints. For example, a(2) = 6 counts 111NNN, 21NNN, 3NNN, 12NNN, 11N1NN, 2N1NN (east steps indicated by their length). If the word "strictly" is replaced by "weakly", the counting sequence becomes the little Schroeder numbers, A001003 (offset).  David Callan, Jun 07 2006
a(n) is the number of dissections of a regular (n+3)gon with base AB that do not contain a triangle of the form ABP with BP a diagonal. Example: a(1) = 2 because the square DC   AB has only 2 such dissections: the empty one and the one with the single diagonal AC (although this dissection contains the triangle ABC, BC is not a diagonal).  David Callan, Jul 14 2006
a(n) is the number of (colored) Motzkin npaths with each upstep and each flatstep at ground level getting one of 2 colors and each flatstep not at ground level getting one of 3 colors. Example: With their colors immediately following upsteps/flatsteps, a(2) = 6 counts U1D, U2D, F1F1, F1F2, F2F1, F2F2.  David Callan, Aug 16 2006
a(n) is the number of separable permutations, i.e., permutations avoiding 2413 and 3142 (see Shapiro and Stephens).  Vincent Vatter, Aug 16 2006
The Hankel transform of this sequence is A006125(n+1) = [1, 2, 8, 64, 1024, 32768, ...]; example: Det([1, 2, 6, 22; 2, 6, 22, 90; 6, 22, 90, 394; 22, 90, 394, 1806 ]) = 64.  Philippe Deléham, Sep 03 2006
Triangle A144156 has row sums equal to A006318 with left border A001003.  Gary W. Adamson, Sep 12 2008
a(n) is also the number of orderpreserving and orderdecreasing partial transformations (of an nchain). Equivalently, it is the order of the Schroeder monoid, PC sub n.  Abdullahi Umar, Oct 02 2008
Sum_{n = 0...infinity} a(n)/10^n  1 = [9sqrt(41)]/2. 1/Sqrt(41) = sum_{n = 0...infinity} Delannoy number(n)/10^n.  Mark Dols (markdols99(AT)yahoo.com), Jun 22 2010
a(n) is also the dimension of the space Hoch(n) related to Hochschild two cocyles.  Ph. Leroux (ph_ler_math(AT)yahoo.com), Aug 24 2010
Let W = (w(n, k)) denote the augmentation triangle (as at A193091) of A154325; then w(n, n) = A006318(n).  Clark Kimberling, Jul 30 2011
Conjecture: For each n > 2, the polynomial sum_{k = 0}^n a(k)*x^{nk} is irreducible modulo some prime p < n*(n+1).  ZhiWei Sun, Apr 07 2013
From Jon Perry, May 24 2013: (Start)
Consider a Pascal triangle variant where T(n, k) = T(n, k1) + T(n1, k1) + T(n1, k), i.e., the order of performing the calculation must go from left to right (A033877). This sequence is the rightmost diagonal.
Triangle begins:
1
1 2
1 4 6
1 6 16 22
1 8 30 68 90
(End)


REFERENCES

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N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).
R. P. Stanley, Enumerative Combinatorics, Cambridge, Vol. 2, 1999; see page 178 and also Problems 6.39 and 6.40.
S.n. Zheng and S.l. Yang, On theShifted Central Coefficients of Riordan Matrices, Journal of Applied Mathematics, Volume 2014, Article ID 848374, 8 pages; http://dx.doi.org/10.1155/2014/848374


LINKS

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E. Barcucci, A. Del Lungo, E. Pergola and R. Pinzani, Permutations avoiding an increasing number of lengthincreasing forbidden subsequences
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Paul Barry, Laurent Biorthogonal Polynomials and Riordan Arrays, arXiv preprint arXiv:1311.2292, 2013
Arkady BERENSTEIN, Vladimir RETAKH, Christophe REUTENAUER and Doron ZEILBERGER, The Reciprocal of Sum_{n >= 0} a^n b^n for noncommuting a and b, Catalan numbers and noncommutative quadratic equations, Arxiv preprint arXiv:1206.4225, 2012.  From N. J. A. Sloane, Nov 28 2012
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W. Y. C. Chen, L. H. Liu and C. J. Wang, Linked Partitions and Permutation Tableaux, arXiv preprint arXiv:1305.5357, 2013
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S.P. Eu and T.S. Fu, A simple proof of the Aztec diamond problem
Luca Ferrari and Emanuele Munarini, Enumeration of edges in some lattices of paths, Arxiv preprint arXiv:1203.6792, 2012.  From N. J. A. Sloane, Oct 03 2012
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Index entries for "core" sequences


FORMULA

G.f.: (1x(16*x+x^2)^(1/2))/(2*x).
a(n) = 2*hypergeom([ n+1, n+2], [2], 1).  Vladeta Jovovic, Apr 24 2003
For n > 0, a(n) = (1/n)*sum(k = 0, n, 2^k*C(n, k)*C(n, k1)).  Benoit Cloitre, May 10 2003
The g.f. satisfies (1x)A(x)xA(x)^2 = 1.  Ralf Stephan, Jun 30 2003
For the asymptotic behavior see A001003 (remembering that A006318 = 2*A001003).  N. J. A. Sloane, Apr 10 2011
Row sums of A088617 and A060693. a(n) = sum (k = 0..n, C(n+k, n)*C(n, k)/k+1).  Philippe Deléham, Nov 28 2003
With offset 1 : a(1) = 1, a(n) = a(n1) + sum(i = 1, n1, a(i)*a(ni)).  Benoit Cloitre, Mar 16 2004
a(n) = sum(k = 0, n, A000108(k)*binomial(n+k, nk)).  Benoit Cloitre, May 09 2004
a(n) = Sum_{k = 0..n} A011117(n, k).  Philippe Deléham, Jul 10 2004
a(n) = (CentralDelannoy[n+1]  3 CentralDelannoy[n])/(2n) = (CentralDelannoy[n+1] + 6 CentralDelannoy[n]  CentralDelannoy[n1])/2 for n>=1 where CentralDelannoy is A001850.  David Callan, Aug 16 2006
The Hankel transform of this sequence is A006125(n+1) = [1, 2, 8, 64, 1024, 32768, ...]; example: Det([1, 2, 6, 22 ; 2, 6, 22, 90; 6, 22, 90, 394; 22, 90, 394, 1806 ]) = 64.  Philippe Deléham, Sep 03 2006
A123164(n+1)  A123164(n) = (2n+1)a (n >= 0);
and 2*A123164(n) = (n+1)a(n)  (n1)a(n1) (n > 0).  Abdullahi Umar, Oct 11 2008
Define the general Delannoy numbers d(i, j) as in A001850. Then a(k) = d(2*k, k)  d(2*k, k1) and a(0) = 1, sum[{(1)^j}*{d(n, j) + d(n1, j1)}*a(nj)] = 0, j = 0, 1, ..., n.  Peter E John, Oct 19 2006
Given an integer t >= 1 and initial values u = [a_0, a_1, ..., a_{t1}], we may define an infinite sequence Phi(u) by setting a_n = a_{n1} + a_0*a_{n1} + a_1*a_{n2} + ... + a_{n2}*a_1 for n >= t. For example, Phi([1]) is the Catalan numbers A000108. The present sequence is (essentially) Phi([2]).  Gary W. Adamson, Oct 27 2008
G.f.: 1/(12x/(1x/(12x/(1x/(12x/(1x/(12x/(1x/(12x/(1x.... (continued fraction).  Paul Barry, Dec 08 2008
G.f.: 1/(1xx/(1xx/(1xx/(1xx/(1xx/(1... (continued fraction).  Paul Barry, Jan 29 2009
a(n) ~ ((3+2*sqrt(2))^n)/(n*sqrt(2*Pi*n)*sqrt(3*sqrt(2)4))*(1(9*sqrt(2)+24)/(32*n)+...).  G. Nemes (nemesgery(AT)gmail.com), Jan 25 2009
Logarithmic derivative yields A002003.  Paul D. Hanna, Oct 25 2010
a(n) = the upper left term in M^(n+1), M = the production matrix:
1, 1, 0, 0, 0, 0,...
1, 1, 1, 0, 0, 0,...
2, 2, 1, 1, 0, 0,...
4, 4, 2, 1, 1, 0,...
8, 8, 8, 2, 1, 1,...
...  Gary W. Adamson, Jul 08 2011
a(n) is the sum of top row terms in Q^n, Q = an infinite square production matrix as follows:
1, 1, 0, 0, 0, 0,...
1, 1, 2, 0, 0, 0,...
1, 1, 1, 2, 0, 0,...
1, 1, 1, 1, 2, 0,...
1, 1, 1, 1, 1, 2,...
...  Gary W. Adamson, Aug 23 2011
From Tom Copeland, Sep 21 2011: (Start)
With F(x) = (13*xsqrt(16*x+x^2))/(2*x) an o.g.f. (nulling the n = 0 term) for A006318, G(x) = x/(2+3*x+x^2) is the compositional inverse.
Consequently, with H(x) = 1/ (dG(x)/dx) = (2+3*x+x^2)^2 / (2x^2),
a(n)=(1/n!)*[(H(x)*d/dx)^n] x evaluated at x = 0, i.e.,
F(x) = exp[x*H(u)*d/du] u, evaluated at u = 0. Also, dF(x)/dx = H(F(x)). (End)
a(n1) = number of ordered complete binary trees with n leaves having k internal vertices colored black, the remaining n  1  k internal vertices colored white, and such that each vertex and its rightmost child have different colors ([Drake, Example 1.6.7]). For a refinement of this sequence see A175124.  Peter Bala, Sep 29 2011
Recurrence: (n2)*a(n2)  3*(2*n1)*a(n1) + (n+1)*a(n) = 0.  Vaclav Kotesovec, Oct 05 2012
G.f.: A(x) = (1  x  sqrt(16x+x^2))/(2*x)= (1  G(0))/x; G(k) = 1 + x  2*x/G(k+1); (continued fraction, 1step).  Sergei N. Gladkovskii, Jan 04 2012
G.f.: A(x) = (1  x  sqrt(16x+x^2))/(2*x)= (G(0)1)/x; G(k)= 1  x/(1  2/G(k+1)); (continued fraction, 2step).  Sergei N. Gladkovskii, Jan 04 2012
a(n+1) = a(n) + sum (a(k)*(nk): k = 0..n).  Reinhard Zumkeller, Nov 13 2012
G.f.: 1/Q(0) where Q(k) = 1 + k*(1x)  x  x*(k+1)*(k+2)/Q(k+1); (continued fraction).  Sergei N. Gladkovskii, Mar 14 2013
a(1n) = a(n).  Michael Somos, Apr 03 2013
G.f.: 1/x  1  U(0)/x, where U(k)= 1  x  x/U(k+1) ; (continued fraction).  Sergei N. Gladkovskii, Jul 16 2013
G.f.: (2  2*x  G(0))/(4*x), where G(k)= 1 + 1/( 1  x*(6x)*(2*k1)/(x*(6x)*(2*k1) + 2*(k+1)/G(k+1) )); (continued fraction).  Sergei N. Gladkovskii, Jul 16 2013


EXAMPLE

a(3) = 22 since the top row of Q^n = (6, 6, 6, 4, 0, 0, 0,...); where 22 = (6 + 6 + 6 + 4).
G.f. = 1 + 2*x + 6*x^2 + 22*x^3 + 90*x^4 + 394*x^5 + 1806*x^6 + 8858*x^7 + 41586*x^8 + ...


MAPLE

Order := 24: solve(series((yy^2)/(1+y), y)=x, y); # then A(x)=y(x)/x
BB:=(1zsqrt(16*z+z^2))/2: BBser:=series(BB, z=0, 24): seq(coeff(BBser, z, n), n=1..23); # Zerinvary Lajos, Apr 10 2007
A006318_list := proc(n) local j, a, w; a := array(0..n); a[0] := 1;
for w from 1 to n do a[w] := 2*a[w1]+add(a[j]*a[wj1], j=1..w1) od; convert(a, list)end: A006318_list(22); # Peter Luschny, May 19 2011
A006318 := n> add(binomial(n+k, nk) * binomial(2*k, k)/(k+1), k=0..n): seq(A006318(n), n=0..22); # Johannes W. Meijer, Jul 14 2013


MATHEMATICA

a[0] = 1; a[n_Integer] := a[n] = a[n  1] + Sum[a[k]*a[n  1  k], {k, 0, n  1}]; Array[a[#] &, 30]
InverseSeries[Series[(y  y^2)/(1 + y), {y, 0, 24}], x] (* then A(x) = y(x)/x  Len Smiley, Apr 11 2000 *)
CoefficientList[Series[(1  x  (1  6x + x^2)^(1/2))/(2x), {x, 0, 30}], x] (* Harvey P. Dale, May 01 2011 *)
a[n_] := 2*Hypergeometric2F1[n + 1, n + 2, 2, 1] (* Michael Somos, Apr 03 2013 *)


PROG

(PARI) {a(n) = if( n<0, n = 1n); polcoeff( (1  x  sqrt( 1  6*x + x^2 + x^2 * O(x^n))) / 2, n+1)}; /* Michael Somos, Apr 03 2013 */
(PARI) {a(n) = if( n<1, 1, sum( k=0, n, 2^k * binomial( n, k) * binomial( n, k1)) / n)}
(Sage) # Generalized algorithm of L. Seidel
def A006318_list(n) :
D = [0]*(n+1); D[1] = 1
b = True; h = 1; R = []
for i in range(2*n) :
if b :
for k in range(h, 0, 1) : D[k] += D[k1]
h += 1;
else :
for k in range(1, h, 1) : D[k] += D[k1]
R.append(D[h1]);
b = not b
return R
A006318_list(23) # Peter Luschny, Jun 02 2012
(Haskell)
a006318 n = a004148_list !! n
a006318_list = 1 : f [1] where
f xs = y : f (y : xs) where
y = head xs + sum (zipWith (*) xs $ reverse xs)
 Reinhard Zumkeller, Nov 13 2012


CROSSREFS

Apart from leading term, twice A001003. Cf. A025240.
Sequences A085403, A086456, A103137, A112478 are essentially the same sequence.
Main diagonal of A033877.
Cf. A088617, A060693. Row sums of A104219. Bisections give A138462, A138463.
Cf. A144156.  Gary W. Adamson, Sep 12 2008
Cf. A002003.  Paul D. Hanna, Oct 25 2010
Row sums of A175124.
Cf. A004148.
Sequence in context: A049134 A086456 * A155069 A103137 A165546 A053617
Adjacent sequences: A006315 A006316 A006317 * A006319 A006320 A006321


KEYWORD

nonn,easy,core,nice


AUTHOR

N. J. A. Sloane


EXTENSIONS

More terms from David W. Wilson
Edited by Charles R Greathouse IV, Apr 20 2010


STATUS

approved



