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A027307 Number of paths from (0,0) to (3n,0) that stay in first quadrant (but may touch horizontal axis) and where each step is (2,1), (1,2) or (1,-1). 49
1, 2, 10, 66, 498, 4066, 34970, 312066, 2862562, 26824386, 255680170, 2471150402, 24161357010, 238552980386, 2375085745978, 23818652359682, 240382621607874, 2439561132029314, 24881261270812490, 254892699352950850 (list; graph; refs; listen; history; text; internal format)
OFFSET

0,2

COMMENTS

Equals row sums of triangle A104978 which has g.f. F(x,y) that satisfies: F = 1 + x*F^2 + x*y*F^3. - Paul D. Hanna, Mar 30 2005

a(n) counts ordered complete ternary trees with 2*n-1 leaves, where the internal vertices come in two colors and such that each vertex and its rightmost child have different colors. See [Drake, Example 1.6.9]. An example is given below. - Peter Bala, Sept 29 2011

REFERENCES

Problem 10658, American Math. Monthly, 107, 2000, 368-370.

J. Winter, M. M. Bonsangue and J. J. M. M. Rutten, Context-free coalgebras, 2013; http://oai.cwi.nl/oai/asset/21313/21313A.pdf

LINKS

Vincenzo Librandi, Table of n, a(n) for n = 0..200

B. Drake, An inversion theorem for labeled trees and some limits of areas under lattice paths (Example 1.6.9), A dissertation presented to the Faculty of the Graduate School of Arts and Sciences of Brandeis University.

FORMULA

G.f.: (2/3)*sqrt((z+3)/z)*sin((1/3)*arcsin(sqrt(z)*(z+18)/(z+3)^(3/2)))-1/3. a(n)=(Sum_{i=0..n-1} 2^(i+1)*binomial(2*n, i)*binomial(n, i+1))/n, n>0.

a(n) = 2*A034015(n-1), n>0.

a(n) = Sum_{k=0..n} C(2*n+k, n+2*k)*C(n+2*k, k)/(n+k+1). - Paul D. Hanna, Mar 30 2005

Given g.f. A(x), y=A(x)x satisfies 0=f(x, y) where f(x, y)=x(x-y)+(x+y)y^2 . - Michael Somos, May 23 2005 */

Series reversion of x(Sum_{k>=0} a(k)x^k) is x(Sum_{k>=0} A085403(k)x^k).

G.f. A(x) satisfies A(x)=A006318(x*A(x)). [Vladimir Kruchinin, Apr 18 2011]

The function B(x) = x*A(x^2) satisfies B(x) = x+x*B(x)^2+B(x)^3 and hence B(x) = compositional inverse of x*(1-x^2)/(1+x^2) = x+2*x^3+10*x^5+66*x^7+.... Let f(x) = (1+x^2)^2/(1-4*x^2+x^4) and let D be the operator f(x)*d/dx. Then a(n) equals 1/(2*n+1)!*D^(2*n)(f(x)) evaluated at x = 0. For a refinement of this sequence see A196201. - Peter Bala, Sep 29 2011

Recurrence: 2*n*(2*n+1)*a(n) = (46*n^2-49*n+12)*a(n-1) - 3*(6*n^2-26*n+27)*a(n-2) - (n-3)*(2*n-5)*a(n-3). - Vaclav Kotesovec, Oct 08 2012

a(n) ~ sqrt(50+30*sqrt(5))*((11+5*sqrt(5))/2)^n/(20*sqrt(Pi)*n^(3/2)). - Vaclav Kotesovec, Oct 08 2012

EXAMPLE

a(3) = 10. Internal vertices colored either b(lack) or w(hite); 5 uncolored leaf vertices shown as o.

........b...........b.............w...........w.....

......./|\........./|\.........../|\........./|\....

....../.|.\......./.|.\........./.|.\......./.|.\...

.....b..o..o.....o..b..o.......w..o..o.....o..w..o..

..../|\............/|\......../|\............/|\....

.../.|.\........../.|.\....../.|.\........../.|.\...

..o..o..o........o..o..o....o..o..o........o..o..o..

....................................................

........b...........b.............w...........w.....

......./|\........./|\.........../|\........./|\....

....../.|.\......./.|.\........./.|.\......./.|.\...

.....w..o..o.....o..w..o.......b..o..o.....o..b..o..

..../|\............/|\......../|\............/|\....

.../.|.\........../.|.\....../.|.\........../.|.\...

..o..o..o........o..o..o....o..o..o........o..o..o..

....................................................

........b...........w..........

......./|\........./|\.........

....../.|.\......./.|.\........

.....o..o..w.....o..o..b.......

........../|\........./|\......

........./.|.\......./.|.\.....

........o..o..o.....o..o..o....

...............................

MATHEMATICA

a[n_] := ((n+1)*(2n)!*Hypergeometric2F1[-n, 2n+1, n+2, -1]) / (n+1)!^2; Table[a[n], {n, 0, 19}] (* Jean-François Alcover, Nov 14 2011, after Pari *)

PROG

(PARI) a(n)=if(n<1, n==0, sum(i=0, n-1, 2^(i+1)*binomial(2*n, i)*binomial(n, i+1))/n)

(PARI) a(n)=sum(k=0, n, binomial(2*n+k, n+2*k)*binomial(n+2*k, k)/(n+k+1)) \\ Paul D. Hanna

(PARI) a(n)=sum(k=0, n, binomial(n, k)*binomial(2*n+k+1, n)/(2*n+k+1) ) /* Michael Somos, May 23 2005 */

CROSSREFS

Cf. A104978. A196201.

Sequence in context: A167449 A064170 A151410 * A060206 A108205 A108397

Adjacent sequences:  A027304 A027305 A027306 * A027308 A027309 A027310

KEYWORD

nonn,changed

AUTHOR

Emeric Deutsch

STATUS

approved

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Last modified May 21 23:25 EDT 2013. Contains 225505 sequences.