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A394887
Terms k in A328116 corresponding to records in A394886.
3
1, 2, 4, 32, 256, 2560, 6144, 155648, 540672, 12288000, 13434880, 25296896, 58982400, 487063552, 800063488, 937426944, 1258291200
OFFSET
1,2
COMMENTS
The values that A051903 (and also A007814) obtains for the 17 initial terms are: 0, 1, 2, 5, 8, 9, 11, 13, 14, 15, 16, 17, 18, 19, 20, 21, 24.
If it exists, a(18) > 2^32.
EXAMPLE
Let x = A276086(a(17)) = A276086(1258291200) = 32470244413303490673777468789898714556998166594933197461202886423699943691 = 7^6 * 11^8 * 13 * 17^13 * 19^13 * 23^14 * 29^5. A099307(x) = 22, so x is in A099308, thus 1258291200 is in A328116, and it is also the first value in that sequence with the maximal exponent (A051903) = 24, which is larger than the previous record, which was 21.
PROG
(PARI)
\\ Uses also the code given in A394886:
m=-1; k=0; for(n=1, 2^35, if(!(n%(2^25)), print1("("n")")); e=A051903(n); if(e>m && is_A328116(n), m=e; k++; write("b394887.txt", k, " ", n); print1(n, "(", m, "), ")));
CROSSREFS
KEYWORD
nonn,more
AUTHOR
Antti Karttunen, Apr 06 2026
STATUS
approved