OFFSET
0,3
FORMULA
Conjecture: a(2^m*(2k+1)) = Sum_{j=0..m} (binomial(m+2, j+1) - binomial(m, j))*a(2^j*k) for m >= 0, k >= 0 with a(0) = 1.
PROG
(PARI) list(n) = my(A, v = vector(n+1, i, 0)); v[1] = 1; for(i=1, n, v[i+1] = v[i\2+1] + if(i%2, 0, A = 1 << valuation(i/2, 2); v[i/2-A+1] + v[i-A+1] + v[i\(4*A)+1])); v
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Mikhail Kurkov, Jan 03 2025
STATUS
approved
