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A378099
The smallest number whose sum of proper divisors (aliquot parts) is the repunit number (10^n - 1)/9, denoted by R_n.
0
2, 21, 321, 7721, 184729, 185145, 21110729, 54929017, 134099385, 3331670169
OFFSET
1,1
EXAMPLE
a(4) = 7721 because 7721 is the smallest number whose sum of proper divisors is R_4 = 1111.
PROG
(PARI) a(n) = my(k=1); while (sigma(k)-k != (10^n - 1)/9, k++); k; \\ Michel Marcus, Nov 16 2024
CROSSREFS
Sequence in context: A234525 A230382 A189489 * A196629 A196637 A240997
KEYWORD
nonn,hard,more
AUTHOR
Shyam Sunder Gupta, Nov 16 2024
STATUS
approved