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A378099
The smallest number whose sum of proper divisors (aliquot parts) is the repunit number A002275(n) = (10^n - 1)/9.
1
1, 2, 21, 321, 7721, 184729, 185145, 21110729, 54929017, 134099385, 3331670169, 287954234809, 330389987289, 4268122018925, 38011695906145, 196584241823289, 5369335816258145, 33333333333333321, 141084098557734969, 9652121670600495449, 29512417650242257465
OFFSET
0,2
COMMENTS
For n >= 2, a(n) <= A073046((A002275(n)-1)/2). - Max Alekseyev, Sep 01 2025
FORMULA
a(n) = A070015(A002275(n)). - Max Alekseyev, Aug 31 2025
EXAMPLE
a(4) = 7721 because 7721 is the smallest number whose sum of proper divisors is A002275(4) = 1111.
PROG
(PARI) a(n) = my(k=1); while (sigma(k)-k != (10^n - 1)/9, k++); k; \\ Michel Marcus, Nov 16 2024
KEYWORD
nonn,hard
AUTHOR
Shyam Sunder Gupta, Nov 16 2024
EXTENSIONS
a(0)=1 prepended and a(11)-a(20) added by Max Alekseyev, Oct 18 2025
STATUS
approved