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A376455
a(n) = least k such that n^(2k+1)/(2k+1)! < 1.
3
1, 1, 2, 3, 4, 6, 7, 8, 10, 11, 12, 14, 15, 16, 18, 19, 20, 22, 23, 24, 26, 27, 28, 30, 31, 32, 34, 35, 36, 38, 39, 41, 42, 43, 45, 46, 47, 49, 50, 51, 53, 54, 55, 57, 58, 59, 61, 62, 64, 65, 66, 68, 69, 70, 72, 73, 74, 76, 77, 78, 80, 81, 83, 84, 85, 87, 88
OFFSET
0,3
COMMENTS
The numbers n^(2k+1)/(2k+1)! are the coefficients in the Maclaurin series for sin x when x = 1. If m>a(n), then n^(2k+1)/(2k+1)! < 1.
MATHEMATICA
a[n_] := Select[Range[z], n^(2 # + 1)/(2 # + 1)! < 1 &, 1]
Flatten[Table[a[n], {n, 0, 100}]]
KEYWORD
nonn
AUTHOR
Clark Kimberling, Oct 17 2024
STATUS
approved