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A376952
a(n) = least k such that (n*Pi/2)^(2k)/(2 k)! < 1.
0
1, 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 23, 25, 27, 29, 31, 33, 35, 37, 39, 42, 44, 46, 48, 50, 52, 54, 56, 59, 61, 63, 65, 67, 69, 71, 73, 76, 78, 80, 82, 84, 86, 88, 91, 93, 95, 97, 99, 101, 103, 105, 108, 110, 112, 114, 116, 118, 120, 122, 125, 127, 129
OFFSET
0,2
COMMENTS
The numbers (n*Pi/2)^(2k)/(2 k)! are the coefficients in the Maclaurin series for cos x when x = n*Pi/2. If m>a(n), then (m*Pi/2)^(2k)/(2 k)! < 1. A375057 is a bisection of this sequence.
FORMULA
a(n) ~ Pi*exp(1)*n/4 - log(n)/4. - Vaclav Kotesovec, Oct 13 2024
MATHEMATICA
a[n_] := Select[Range[300], (n Pi/2)^(2 #)/(2 #)! < 1 &, 1];
Flatten[Table[a[n], {n, 0, 200}]]
KEYWORD
nonn,new
AUTHOR
Clark Kimberling, Oct 12 2024
STATUS
approved