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A373216
Expansion of Sum_{k>=0} x^(6^k) / (1 - x^(6^k)).
9
1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 3, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 3, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 3
OFFSET
1,6
LINKS
FORMULA
G.f. A(x) satisfies A(x) = x/(1 - x) + A(x^6).
a(6*n+1) = a(6*n+2) = ... = (6*n+5) = 1 and a(6*n+6) = 1 + a(n+1) for n >= 0.
a(n) = A122841(n) + 1.
G.f.: Sum_{i>=1, j>=0} x^(i*6^j). - Seiichi Manyama, Mar 23 2025
a(n) = A122841(6*n). - R. J. Mathar, Jun 28 2025
From Amiram Eldar, Feb 19 2026: (Start)
Dirichlet g.f.: (6^s/(6^s-1)) * zeta(s).
Asymptotic mean: Limit_{m->oo} (1/m) * Sum_{k=1..m} a(k) = 6/5. (End)
Sum_{k=1..n} a(k) ~ 6*n/5 - log(n)/log(36). - Vaclav Kotesovec, Feb 20 2026
MAPLE
a:= n-> padic[ordp](n, 6)+1:
seq(a(n), n=1..108); # Alois P. Heinz, Feb 20 2026
MATHEMATICA
a[n_] := IntegerExponent[n, 6] + 1; Array[a, 108] (* Amiram Eldar, Feb 19 2026 *)
PROG
(PARI) a(n) = valuation(n, 6)+1;
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Seiichi Manyama, May 28 2024
STATUS
approved