OFFSET
1,2
COMMENTS
The sequence is conjectured to be integral.
LINKS
Paolo Xausa, Table of n, a(n) for n = 1..300
FORMULA
a(n) = sqrt( (T(2*n, 2*n+1) - 1)/((n+1)*(2*n)^3) ), where T(n, x) is the n-th Chebyshev polynomial of the first kind.
MAPLE
MATHEMATICA
Table[Sqrt[(ChebyshevT[2*n, 2*n + 1] - 1)/(2*n)^3/(n + 1)], {n, 20}] (* Paolo Xausa, Jul 24 2024 *)
PROG
(Python)
from math import isqrt
from sympy import chebyshevt
def A370261(n): return isqrt((chebyshevt((m:=n<<1), m+1)-1)//((n+1)*m**3)) # Chai Wah Wu, Mar 13 2024
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Peter Bala, Mar 11 2024
STATUS
approved