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A366123 The number of prime factors of the cube root of the largest cube dividing n, counted with multiplicity. 1
0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,64
COMMENTS
First differs from A295659 at n = 64.
The number of distinct prime factors of the cube root of the largest cube dividing n is A295659(n).
LINKS
FORMULA
a(n) = A001222(A053150(n)).
a(n) = A001222(A008834(n))/3.
Additive with a(p^e) = floor(e/3) = A002264(e).
a(n) >= 0, with equality if and only if n is cubefree (A004709).
a(n) <= A001222(n)/3, with equality if and only if n is a positive cube (A000578 \ {0}).
Asymptotic mean: Limit_{m->oo} (1/m) * Sum_{k=1..m} a(k) = Sum_{p prime} 1/(p^3-1) = 0.194118... (A286229).
MATHEMATICA
f[p_, e_] := Floor[e/3]; a[1] = 0; a[n_] := Plus @@ f @@@ FactorInteger[n]; Array[a, 100]
PROG
(PARI) a(n) = vecsum(apply(x -> x\3, factor(n)[, 2]));
CROSSREFS
Cf. A061704 (number of divisors), A333843 (sum of divisors).
Sequence in context: A244413 A318655 A056626 * A290081 A347706 A348381
KEYWORD
nonn,easy
AUTHOR
Amiram Eldar, Sep 30 2023
STATUS
approved

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Last modified June 30 18:22 EDT 2024. Contains 373877 sequences. (Running on oeis4.)