A363870 a(n) = A108625(n, 3*n).

1, 7, 127, 2869, 71631, 1894007, 51978529, 1464209383, 42050906191, 1225778575021, 36156060825127, 1076772406867549, 32324178587781393, 976893529756053501, 29693248490460447747, 907027175886637081619, 27826656707376811715663, 856949305975908664414097

Offset

0,2

Comments

a(n) = B(n, 3*n, n) in the notation of Straub, equation 24. It follows from Straub, Theorem 3.2, that the supercongruences a(n*p^k) == a(n*p^(k-1)) (mod p^(3*k)) hold for all primes p >= 5 and all positive integers n and k.

More generally, for positive integers r and s the sequence {A108625(r*n, s*n) : n >= 0} satisfies the same supercongruences.

For other cases, see A099601 (r = 2, s = 1), A363867 (r = 1, s = 2), A363868 (r = 3, s = 1), A363869 (r = 3, s = 2) and A363871 (r = 2, s = 3).

Links

G. C. Greubel, Table of n, a(n) for n = 0..500

Peter Bala, A recurrence for A363870

Formula

a(n) = Sum_{k = 0..n} binomial(n, k)^2 * binomial(3*n+k, n).

a(n) = Sum_{k = 0..n} (-1)^(n+k) * binomial(n, k)*binomial(3*n+k, n)^2.

a(n) = hypergeometric3F2( [-n, -3*n, n+1], [1, 1], 1).

a(n) = [x^(3*n)] 1/(1 - x)*Legendre_P(n, (1 + x)/(1 - x)).

a(n) ~ sqrt(25 + 151/sqrt(37)) * (11906 + 1961*sqrt(37))^n / (Pi * 2^(3/2) * n * 3^(6*n+1)). - Vaclav Kotesovec, Feb 17 2024

a(n) = Sum_{k = 0..n} binomial(n, k)*binomial(n+k, k)*binomial(3*n, k). - Peter Bala, Feb 25 2024

Maple

A108625 := (n, k) -> hypergeom([-n, -k, n+1], [1, 1], 1):
seq(simplify(A108625(n, 3*n)), n = 0..20);

Mathematica

Table[HypergeometricPFQ[{-n, -3*n, n+1}, {1, 1}, 1], {n, 0, 30}] (* G. C. Greubel, Oct 05 2023 *)

Prog

(Magma)
A363870:= func< n | (&+[Binomial(n, j)^2*Binomial(3*n+j, n): j in [0..n]]) >;
[A363870(n): n in [0..30]]; // G. C. Greubel, Oct 05 2023
(SageMath)
def A363870(n): return sum(binomial(n, j)^2*binomial(3*n+j, n) for j in range(n+1))
[A363870(n) for n in range(31)] # G. C. Greubel, Oct 05 2023

Crossrefs

Cf. A005258, A099601, A108625, A363864 - A363871.

Sequence in context: A241955 A139291 A274673 * A215066 A092676 A002067

Adjacent sequences: A363867 A363868 A363869 * A363871 A363872 A363873

Keyword

nonn,easy

Author

Peter Bala, Jun 27 2023

Status

approved