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A341932
a(n) = largest k < n such that the decimal concatenation n||n-1||n-2||...||n-k is prime, or -1 if no such prime exists.
2
-1, -1, 0, 0, 1, 0, -1, 4, -1, -1, 3, 0, -1, 0, -1, -1, -1, 0, -1, 0, -1, -1, 3, 0, 1, 12, -1, 4, -1, 0, -1, 0, -1, -1, 1, -1, -1, 0, -1, -1, -1, 0, 1, 0, -1, -1, 43, 0, 31, -1, -1, 4, 15, 12, -1, 28, 9, -1, 1, 0, 13, 0, -1, -1, -1, -1, -1, 0, 57, -1, 1, 0, -1
OFFSET
0,8
COMMENTS
a(82) = 81, are there any other n such that a(n) = n-1?
Primes p such that a(p) > 0: 7, 53, 73, 79, 89, 103, ...
n such that a(n) > A341702(n): 7, 10, 22, 46, 48, 53, 55, 73, ...
Similar argument as in A341716 shows that if n > 3 and a(n) >= 0, then n-a(n) is odd, a(n) !== 2 (mod 3) and 2n-a(n) !== 0 (mod 3).
FORMULA
a(n) = n-A341931(n) >= A341702(n).
EXAMPLE
a(22) = 3 since 22212019 is prime.
PROG
(Python)
from sympy import isprime
def A341932(n):
k, m, r = n, n-1, 0 if isprime(n) else -1
while m > 0:
k = int(str(k)+str(m))
if isprime(k):
r = n-m
m -= 1
return r
KEYWORD
sign,base
AUTHOR
Chai Wah Wu, Feb 23 2021
STATUS
approved