OFFSET
1,1
COMMENTS
With this constant r(1) and using the formula r(n+1) = round(r(n))*(r(n) - round(r(n)) + 1.5) it is possible to obtain the sequence of prime numbers because round(r(n)) = prime(n).
FORMULA
r(1) = Sum_{k>=1} (prime(k)-1.5)/Product_{i=1..k-1} prime(i).
EXAMPLE
2.06743589142023422951884707566789...
PROG
(PARI) suminf(k=1, (prime(k)-1.5)/prod(i=1, k-1, prime(i))) \\ Michel Marcus, Feb 23 2021
CROSSREFS
KEYWORD
nonn,cons
AUTHOR
Davide Rotondo, Feb 23 2021
STATUS
approved