OFFSET
1,2
COMMENTS
There cannot be 8 consecutive cubefree numbers since one of them must be divisible by 8 = 2^3.
All the terms are congruent to 1 mod 8.
The asymptotic density of this sequence is A328017.
LINKS
Amiram Eldar, Table of n, a(n) for n = 1..10000
Leon Mirsky, Arithmetical pattern problems relating to divisibility by rth powers, Proceedings of the London Mathematical Society, Vol. s2-50, No. 1 (1949), pp. 497-508.
EXAMPLE
9 is in the sequence since the numbers 9, 10, ... 15 are all cubefree.
MATHEMATICA
cubeFreeQ[n_] := FreeQ[FactorInteger[n], {_, k_ /; k > 2}]; aQ[n_] := AllTrue[n + Range[0, 6], cubeFreeQ]; Select[Range[650], aQ]
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Amiram Eldar, Oct 01 2019
STATUS
approved