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 A298110 Solution (b(n)) of the near-complementary equation a(n) = a(1)*b(n) - a(0)*b(n-1) + n, where a(0) = 1, a(1) = 2, b(0) = 3, b(1) = 4, b(2) = 5, and (b(n)) is the increasing sequence of positive integers not in (a(n)).  See Comments. 3
 3, 4, 5, 6, 7, 9, 11, 13, 14, 15, 17, 18, 20, 21, 24, 26, 27, 28, 31, 32, 33, 36, 37, 38, 39, 40, 42, 45, 47, 48, 49, 50, 51, 53, 55, 56, 57, 58, 59, 61, 63, 65, 67, 68, 69, 71, 72, 73, 74, 76, 79, 81, 83, 85, 86, 87, 89, 90, 93, 95, 97, 99, 100, 101, 103 (list; graph; refs; listen; history; text; internal format)
 OFFSET 0,1 COMMENTS The sequence (a(n)) generated by the equation a(n) = a(1)*b(n-1) - a(0)*b(n-2) + n, with initial values as shown, includes duplicates; e.g. a(18) = a(19) = 51.  If the duplicates are removed from (a(n)), the resulting sequence and (b(n)) are complementary. Conjectures: (1) 1 <= b(k) - b(k-1) <= 3 for k>=1; (2) if d is in {1,2,3}, then b(k) = b(k-1) + d for infinitely many k. *** See A298000 and A297830 for guides to related sequences. LINKS Clark Kimberling, Table of n, a(n) for n = 0..2000 EXAMPLE a(0) = 1, a(1) = 2, b(0) = 3, b(1) = 4, b(2) = 5, so that a(2) = 8. Complement: A298110 = (3,4,5,6,7,9,11,13,14,15,17, ...) MATHEMATICA mex[list_, start_] := (NestWhile[# + 1 &, start, MemberQ[list, #] &]); a[0] = 1; a[1] = 2; b[0] = 3; b[1] = 4; b[2] = 5; a[n_] := a[1]*b[n] - a[0]*b[n - 1] + n; Table[{a[n], b[n + 1] = mex[Flatten[Map[{a[#], b[#]} &, Range[0, n]]], b[n - 0]]}, {n, 2, 3000}]; Table[a[n], {n, 0, 150}]  (* A297999 *) Table[b[n], {n, 0, 150}]  (* A298110 *) (* Peter J. C. Moses, Jan 16 2018 *) CROSSREFS Cf. A297999, A298000, A297830. Sequence in context: A039051 A047564 A154536 * A091815 A081692 A161346 Adjacent sequences:  A298107 A298108 A298109 * A298111 A298112 A298113 KEYWORD nonn,easy AUTHOR Clark Kimberling, Feb 09 2018 STATUS approved

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Last modified December 5 06:44 EST 2020. Contains 338944 sequences. (Running on oeis4.)