OFFSET
1,1
COMMENTS
a(n) consists of the number of forms 16*(8i + 7) (0 <= i <= 152) and 64*(8j + 7) (0 <= j <= 37).
The last term in this sequence is a(191) = 19568 = 16*(8*152 + 7) (see A297970).
LINKS
MATHEMATICA
t1=Table[4^2*(8j+7), {j, 0, 152}];
t2=Table[4^3*(8j+7), {j, 0, 37}];
t=Union[t1, t2]
CROSSREFS
KEYWORD
nonn,fini,full
AUTHOR
XU Pingya, Jan 30 2018
STATUS
approved