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 A296215 Solution of the complementary equation a(n) = a(1)*b(n-2) + a(2)*b(n-3) + ... + a(n-1)*b(0), where a(0) = 1, a(1) = 3, b(0) = 2, and (a(n)) and (b(n)) are increasing complementary sequences. 4
 1, 3, 6, 24, 87, 321, 1176, 4314, 15822, 58032, 212847, 780672, 2863317, 10501959, 38518662, 141277197, 518170812, 1900526031, 6970672818, 25566752964, 93772706622, 343935755925, 1261473710904, 4626782461218, 16969926331719, 62241612204120, 228287277978756 (list; graph; refs; listen; history; text; internal format)
 OFFSET 0,2 COMMENTS The increasing complementary sequences a() and b() are uniquely determined by the titular equation and initial values. See A295862 for a guide to related sequences. LINKS Table of n, a(n) for n=0..26. Clark Kimberling, Complementary equations, J. Int. Seq. 19 (2007), 1-13. EXAMPLE a(0) =1, a(1) = 3, b(0) = 2, b(1) = 4, b(2) = 5 a(2) = a(1)*b(0) = 6 Complement: (b(n)) = (2, 4, 5, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, ...) MATHEMATICA a = 1; a = 3; b = 2; a[n_] := a[n] = Sum[a[k]*b[n - k - 1], {k, 1, n - 1}]; b[n_] := b[n] = mex[Flatten[Table[Join[{a[n]}, {a[i], b[i]}], {i, 0, n - 1}]]]; u = Table[a[n], {n, 0, 200}]; (* A296215 *) Table[b[n], {n, 0, 20}] N[Table[a[n]/a[n - 1], {n, 1, 200, 10}], 200]; RealDigits[Last[t], 10][] (* A296216 *) CROSSREFS Cf. A296000, A296217. Sequence in context: A132390 A363016 A327643 * A152761 A295761 A262349 Adjacent sequences: A296212 A296213 A296214 * A296216 A296217 A296218 KEYWORD nonn,easy AUTHOR Clark Kimberling, Dec 08 2017 STATUS approved

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Last modified December 7 21:37 EST 2023. Contains 367662 sequences. (Running on oeis4.)