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A294602
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a(n) = pi(n-1) - pi(floor(n/2)), where pi is A000720.
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4
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0, 0, 1, 1, 1, 1, 1, 2, 2, 1, 1, 2, 2, 2, 2, 2, 2, 3, 3, 4, 4, 3, 3, 4, 4, 3, 3, 3, 3, 4, 4, 5, 5, 4, 4, 4, 4, 4, 4, 4, 4, 5, 5, 6, 6, 5, 5, 6, 6, 6, 6, 6, 6, 7, 7, 7, 7, 6, 6, 7, 7, 7, 7, 7, 7, 7, 7, 8, 8, 8, 8, 9, 9, 9, 9, 9, 9, 9, 9, 10, 10, 9, 9, 10, 10, 9
(list;
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refs;
listen;
history;
text;
internal format)
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OFFSET
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1,8
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COMMENTS
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Number of primes in the interval (n/2, n).
Number of primes among the larger parts of the partitions of n into two distinct parts. For n=8, the partitions of 8 into two distinct parts are (7,1), (6,2), (5,3); 7 and 5 are prime so a(8) = 2. - Wesley Ivan Hurt, Apr 07 2018
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LINKS
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FORMULA
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EXAMPLE
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a(8) = 2 because there are 2 primes between 4 and 8: 5, 7.
a(19) = 3 because there are 3 primes between 9 and 19: 11, 13, 17.
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MAPLE
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numtheory[pi](n-1)-numtheory[pi](floor(n/2)) ;
end proc:
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MATHEMATICA
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PROG
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(Magma) [0, 0] cat [#PrimesInInterval(Floor(n/2)+1, n-1): n in [3..86]];
(PARI) vector(86, n, primepi(n-1)-primepi(n\2))
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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