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A283446 Integer areas of triangles with side lengths A001223(m), A001223(m+1) and A001223(m+2) for some m. 1
24, 96, 120, 144, 168, 216, 240, 264, 336, 360, 384, 432, 456, 480, 504, 528, 576, 600, 624, 672, 720, 792, 816, 840, 864, 936, 960, 1008, 1056, 1080, 1176, 1200, 1224, 1296, 1320, 1344, 1440, 1512, 1536, 1560, 1584, 1680, 1728, 1824, 1848, 1920, 1944, 2016 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,1
COMMENTS
A001223(n) = A000040(n+1) - A000040(n) = prime(n+1) - prime(n).
The Mathematica program examines all triangles with n <= 10^8.
The sequence a(n) is a subsequence of A188158, and the lengths of the sides are even.
The area A of a triangle whose sides have lengths a, b, and c is given by Heron's formula: A = sqrt(s*(s-a)*(s-b)*(s-c)), where s = (a+b+c)/2.
a(n) == 0 mod 24 => {b(n)} = {a(n)/24} = {1, 4, 5, 6, 7, 9, 10, 11, 14, 15, 16, 18, 19, 20, 21, 22, 24, 25, 26, 28, 30, 33, 34, 35, 36, 39, 40, 42, 44, 45, 49, 51, 54, 55, 56, 60, 63, 64, 65, 70, 72, ...}. It seems that the primes > 19 are not in {b(n)}.
For the same area, the number of distinct triangles is not always unique; for example, the area 336 can be obtained with triangle (30, 28, 26) starting from prime 461983 and also from triangle (34, 20, 42) starting from prime 2473663 (Giovanni Resta, Mar 08 2017).
The following table gives the first values (A, m, sides of the triangles) where A is the area of the triangles and m is the smallest value generating A.
+-----+--------+-----------+-------------+-------------+
| A | m | A001223(m)| A001223(m+1)| A001223(m+2)|
+-----+--------+-----------+-------------+-------------+
| 24 | 123 | 6 | 8 | 10 |
| 96 | 3935 | 16 | 20 | 12 |
| 120 | 8101 | 10 | 26 | 24 |
| 144 | 13097 | 34 | 18 | 20 |
| 168 | 12226 | 30 | 40 | 14 |
| 216 | 9864 | 24 | 18 | 30 |
| 240 | 102715 | 58 | 50 | 12 |
| 264 | 98259 | 22 | 26 | 40 |
| 336 | 38604 | 30 | 28 | 26 |
+-----+--------+-----------+-------------+-------------+
LINKS
EXAMPLE
24 is in the sequence because, for the smallest value m = 123, we obtain the triangle of sides (A001223(123), A001223(124), A001223(125)) = (6, 8, 10) and the area is given by Heron's formula with s = 12 and A = sqrt(12(12-6)(12-8)(12-10)) = 24.
The set of the others values m > 123 giving the same area A = 24 starts with 127, 192, 269, 304, 417, 420, ...
MATHEMATICA
nn=10^5; lst={}; Do[u=Prime[a+1]-Prime[a]; v=Prime[a+2]-Prime[a+1]; w=Prime[a+3]-Prime[a+2]; s=(u+v+w)/2; If[IntegerQ[s], area2=s (s-u)(s-v)(s-w); If[area2>0&&IntegerQ[Sqrt[area2]], AppendTo[lst, Sqrt[area2]]]], {a, nn}]; Union[lst]
CROSSREFS
Sequence in context: A353326 A055671 A090214 * A208984 A103251 A256418
KEYWORD
nonn
AUTHOR
Michel Lagneau, Mar 08 2017
EXTENSIONS
Missing terms 1200 and 1584 from Giovanni Resta, Mar 08 2017
STATUS
approved

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Last modified April 24 19:06 EDT 2024. Contains 371962 sequences. (Running on oeis4.)