

A256418


Congrua (possible solutions to the congruum problem): numbers n such that there are integers x, y and z with n = x^2y^2 = z^2x^2.


17



24, 96, 120, 216, 240, 336, 384, 480, 600, 720, 840, 864, 960, 1080, 1176, 1320, 1344, 1536, 1920, 1944, 2016, 2160, 2184, 2400, 2520, 2880, 2904, 3000, 3024, 3360, 3456, 3696, 3840, 3960, 4056, 4320, 4704, 4896, 5280, 5376, 5400, 5544
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OFFSET

1,1


COMMENTS

n is a "congruum" iff n/4 is the area of a Pythagorean triangle, so these are the numbers 4*A009112.
Each congruum is a multiple of 24; it cannot be a square.


LINKS

Eric Weisstein's World of Mathematics, Congruum (but beware errors)
Wikipedia, Congruum (but beware errors).


EXAMPLE

a(11)=840 since 840=29^21^2=41^229^2 (indeed also 840=37^223^2=47^237^2).


MATHEMATICA

r[n_] := Reduce[0 < y < x && 0 < x < z && n == x^2  y^2 == z^2  x^2, {x, y, z}, Integers];
Reap[For[n = 24, n < 10^4, n += 24, rn = r[n]; If[rn =!= False, Print[n, " ", rn]; Sow[n]]]][[2, 1]] (* JeanFrançois Alcover, Feb 25 2019 *)


CROSSREFS

Cf. A004431 for possible values of x in definition. Cf. A057103, A055096 for triangles of all congrua and values of x.


KEYWORD

nonn


AUTHOR



STATUS

approved



