login

Year-end appeal: Please make a donation to the OEIS Foundation to support ongoing development and maintenance of the OEIS. We are now in our 61st year, we have over 378,000 sequences, and we’ve reached 11,000 citations (which often say “discovered thanks to the OEIS”).

A260674
Primes p for which the greatest common divisor of 2^p+1 and 3^p+1 is greater than 1.
3
2, 83, 107, 367, 569, 887, 1327, 1451, 1621, 1987, 2027, 3307, 3547, 3631, 3691, 4421, 4547, 4967, 5669, 5843, 5927, 6011, 6911, 6991, 7207, 7949, 8167, 8431, 10771, 10889, 11287, 11621, 12007, 12227, 12487, 12763, 12983, 15391, 15767, 16127, 17107, 17183, 17231
OFFSET
1,1
COMMENTS
Primes p such that A066803(p)>1. - Tom Edgar, Nov 15 2015
LINKS
Carlos Rivera, Puzzle 1064. GCD(2^p+1,3^p+1), The Prime Puzzles and Problems Connection.
EXAMPLE
Since GCD(2^83 + 1, 3^83 + 1) = 499, the prime 83 is in the sequence. It is only the second such prime, so a(2) = 83.
MATHEMATICA
Select[Prime@ Range@ 2000, GCD[2^# + 1, 3^# + 1] > 1 &] (* Michael De Vlieger, Nov 16 2015 *)
PROG
(Sage)
# code will list all such primes no larger than the N-th prime.
N=1000
for k in range(N):
if (gcd(2^Primes().unrank(k)+1, 3^Primes().unrank(k)+1) != 1):
print(Primes().unrank(k))
(PARI) list(lim)=forprime(p=2, lim, if(gcd(2^p+1, 3^p+1)>1, print1(p, ", "))) \\ Anders Hellström, Nov 14 2015
(Python)
from sympy import prime
from fractions import gcd
A260674_list = [p for p in (prime(n) for n in range(1, 10**3)) if gcd(2**p+1, 3**p+1) > 1] # Chai Wah Wu, Nov 23 2015
CROSSREFS
KEYWORD
nonn
AUTHOR
Alex Jordan, Nov 14 2015
STATUS
approved