A259003 Number of (n+2)X(5+2) 0..1 arrays with every 3X3 subblock sum of the two medians of the central row and column plus the two sums of the diagonal and antidiagonal nondecreasing horizontally, vertically and ne-to-sw antidiagonally

113474, 131557, 397152, 402742, 219424, 210946, 35404, 30072, 23070, 28125, 28868, 27162, 31876, 24996, 25262, 23934, 28976, 39602, 26248, 29360, 24542, 29960, 30788, 29082, 33796, 26916, 27182, 25854, 30896, 41522, 28168, 31280, 26462, 31880, 32708

Offset

1,1

Comments

Column 5 of A259006

Links

R. H. Hardin, Table of n, a(n) for n = 1..210

Formula

Empirical: a(n) = a(n-1) +a(n-12) -a(n-13) for n>23

Empirical for n mod 12 = 0: a(n) = 160*n + 25242 for n>10

Empirical for n mod 12 = 1: a(n) = 160*n + 29796 for n>10

Empirical for n mod 12 = 2: a(n) = 160*n + 22756 for n>10

Empirical for n mod 12 = 3: a(n) = 160*n + 22862 for n>10

Empirical for n mod 12 = 4: a(n) = 160*n + 21374 for n>10

Empirical for n mod 12 = 5: a(n) = 160*n + 26256 for n>10

Empirical for n mod 12 = 6: a(n) = 160*n + 36722 for n>10

Empirical for n mod 12 = 7: a(n) = 160*n + 23208 for n>10

Empirical for n mod 12 = 8: a(n) = 160*n + 26160 for n>10

Empirical for n mod 12 = 9: a(n) = 160*n + 21182 for n>10

Empirical for n mod 12 = 10: a(n) = 160*n + 26440 for n>10

Empirical for n mod 12 = 11: a(n) = 160*n + 27108 for n>10

Example

Some solutions for n=2
..1..1..0..1..0..1..0....1..1..0..1..1..1..0....0..0..0..0..1..0..1
..1..0..0..1..0..1..0....0..0..0..0..0..1..0....1..0..0..0..0..1..0
..1..0..1..1..1..1..1....0..1..1..1..1..1..0....0..0..0..1..1..1..0
..1..1..0..0..1..0..1....1..1..0..1..1..0..1....0..1..0..1..1..0..1

Crossrefs

Cf. A259006

Sequence in context: A172692 A172648 A259010 * A256901 A066790 A135411

Adjacent sequences: A259000 A259001 A259002 * A259004 A259005 A259006

Keyword

nonn

Author

R. H. Hardin, Jun 16 2015

Status

approved