OFFSET
1,1
COMMENTS
This sequence is probably finite with 228 terms. The probable last term of the sequence is a(228) = 6903, and the corresponding Lucas number A000032(6903) = 4382083468497... 10084254004 contains 1443 decimal digits.
LINKS
Michel Lagneau, Table of n, a(n) for n = 1..228
MAPLE
with(combinat, fibonacci):with(numtheory):
a:=n->2*fibonacci(n-1)+fibonacci(n):
for m from 1 to 400 do:
x:=a(m):y:=convert(x, base, 10):n1:=nops(y):
s:=sum('y[i]', 'i'=1..n1):
if s>m
then
printf(`%d, `, m):
else
fi:
od:
PROG
(PARI) lista(nn) = {for(n=1, nn, if (sumdigits(l = fibonacci(n+1) + fibonacci(n-1)) > n, print1(n, ", "))); } \\ Altug Alkan, Nov 08 2015
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Michel Lagneau, Nov 07 2015
STATUS
approved