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 A253302 Smallest integer m such that gcd{x | sum of proper divisors of x is m} is equal to n, when there are at least two such x's. 1
 1, 16, 300, 136, 50316, 186, 97748, 1352, 72318, 1340, 1652, 1356 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,2 COMMENTS Only integers m that satisfy A048138(m) > 1 are considered here. Other known terms with odd indices: a(25)=39926, a(49)=46850. For terms with even indices see A253303. LINKS Table of n, a(n) for n=1..12. EXAMPLE For every prime p the sum of proper divisors of p is 1, and the GCD of the primes is 1, so a(1) = 1. PROG (PARI) build(nb) = {vs = vector(nb); nc = nb^2; forcomposite(n=2, nc, val = sigma(n)-n; if (val <= nb, if (vs[val] == 0, vs[val] = -n, vs[val] = gcd(vs[val], n)); ); ); vs = 1; vs; } lista() = {vd = build(100000); vmax = 20; vr = vector(vmax); for (ig=1, vmax, for (i=1, #vd, w = vd[i]; if (w ==ig, vr[ig] = i; break; ); ); ); for (i=1, #vr, if (vr[i] == 0, break, print1(vr[i], ", "))); } CROSSREFS Cf. A001065 (sum of proper divisors), A048138, A152454, A253303. Sequence in context: A299672 A299750 A300264 * A227678 A252863 A360431 Adjacent sequences: A253299 A253300 A253301 * A253303 A253304 A253305 KEYWORD nonn,more AUTHOR Michel Marcus, Dec 30 2014 EXTENSIONS a(1)=1 suggested by Robert Israel, Jan 01 2015 STATUS approved

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Last modified September 22 18:47 EDT 2023. Contains 365531 sequences. (Running on oeis4.)