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A247205
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Numbers k such that 2*k^2 - 1 divides 2^k - 1.
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1
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OFFSET
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1,2
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COMMENTS
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LINKS
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EXAMPLE
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1 is in this sequence because 2*1^2 - 1 = 1 divides 2^1 - 1 = 1.
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PROG
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(Magma) [n: n in [1..100000] | Denominator((2^n-1)/(2*n^2-1)) eq 1];
(PARI) for(n=1, 10^9, if(Mod(2, 2*n^2-1)^n==+1, print1(n, ", "))); \\ Joerg Arndt, Nov 30 2014
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CROSSREFS
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KEYWORD
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nonn,more,bref
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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