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A242796
Least number k such that (k^k-n)/(k-n) is prime, or 0 if no such k exists.
0
2, 4, 6, 5, 0, 13, 9, 11, 0, 12, 22, 13, 37, 28, 36, 0, 0, 171, 73, 85, 0, 0, 0, 29, 0, 0, 0, 0, 517, 35, 40, 49, 44, 49, 0, 41, 46, 40, 0, 0, 51, 0, 52, 0, 0, 0, 0, 0, 0, 0, 0, 0, 2841, 0, 0, 0, 0, 0, 0, 67, 0, 64, 0, 199, 125, 221, 0, 0, 153, 113, 239, 0, 97, 0, 0, 0
OFFSET
1,1
COMMENTS
a(n)=0 is confirmed for k <= 5000.
EXAMPLE
(1^1-2)/(1-2) = 1 is not prime. (3^3-2)/(3-2) = 25 is not prime. (4^4-2)/(4-2) = 254/2 = 127 is prime. Thus a(2) = 4.
PROG
(PARI) a(n)=for(k=1, 5000, if(k!=n, s=(k^k-n)/(k-n); if(floor(s)==s, if(ispseudoprime(s), return(k)))));
n=1; while(n<100, print(a(n)); n+=1)
CROSSREFS
Sequence in context: A365160 A082747 A127275 * A298527 A071288 A063892
KEYWORD
nonn,more,hard
AUTHOR
Derek Orr, May 22 2014
EXTENSIONS
We don't normally allow conjectural terms, except in special circumstances. This is one of those exceptions, for if we included only terms that are known for certain, not much of this sequence would remain. - N. J. A. Sloane, May 31 2014
STATUS
approved