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A226703 Triangle read by rows: T(n,k) = binomial(2*n,k)*Stirling2(2*n-k,n). 0
1, 1, 2, 7, 12, 6, 90, 150, 90, 20, 1701, 2800, 1820, 560, 70, 42525, 69510, 47250, 16800, 3150, 252, 1323652, 2153844, 1506582, 582120, 131670, 16632, 924, 49329280, 80015936, 57093036, 23291268, 5885880, 924924, 84084, 3432, 2141764053, 3466045440, 2509478400, 1063782720, 289429140, 51891840, 6006000, 411840, 12870 (list; table; graph; refs; listen; history; text; internal format)
OFFSET
0,3
COMMENTS
Polynomials based on Extended Tepper's Identity
P(n,x)=sum(j=0..n, (-1)^(n-j)*binomial(n,j)*(x+j)^(2*n))/n!.
P(n,x)=sum(j=0..n, binomial(2*n,j)*stirling2(2*n-j,n)*x^j).
P(n,1)=A129506(n).
REFERENCES
G. P. Egorychev. “Integral Representation and the Computation of Combinatorial Sums.” Translations of Mathematical Monographs, Vol. 59, American Mathematical Society, (1984).
F. J. Papp. “Another Proof of Tepper’s Inequality.” Math. Magazine 45 (1972): 119-121.
LINKS
FORMULA
T(n,k) = binomial(2*n,k)*stirling2(2*n-k,n).
T(n,n) = A000984(n).
T(n,0) = A007820(n).
EXAMPLE
1,
1 +2*x,
7 +12*x +6*x^2,
90 +150*x +90*x^2 +20*x^3,
1701 +2800*x +1820*x^2 +560*x^3 +70*x^4.
MATHEMATICA
Flatten[Table[Binomial[2n, k]StirlingS2[2n-k, n], {n, 0, 10}, {k, 0, n}]] (* Harvey P. Dale, Jun 19 2013 *)
CROSSREFS
Sequence in context: A069748 A064441 A110949 * A126343 A344951 A174539
KEYWORD
nonn,tabl
AUTHOR
Vladimir Kruchinin, Jun 15 2013
STATUS
approved

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Last modified April 25 07:41 EDT 2024. Contains 371964 sequences. (Running on oeis4.)