A209998 Triangle of coefficients of polynomials v(n,x) jointly generated with A209996; see the Formula section.

1, 2, 3, 2, 8, 9, 2, 10, 30, 27, 2, 10, 46, 108, 81, 2, 10, 50, 198, 378, 243, 2, 10, 50, 242, 810, 1296, 729, 2, 10, 50, 250, 1122, 3186, 4374, 2187, 2, 10, 50, 250, 1234, 4986, 12150, 14580, 6561, 2, 10, 50, 250, 1250, 5946, 21330, 45198, 48114, 19683

Offset

1,2

Comments

Row n starts 2, 2*5, 2*5^2,... ; ends with 3^(n-1).

Conjecture: penultimate term in row n is A199923(n).

Alternating row sums: A077925

For a discussion and guide to related arrays, see A208510.

Links

Table of n, a(n) for n=1..55.

Formula

u(n,x)=x*u(n-1,x)+2x*v(n-1,x)+1,

v(n,x)=(x+1)*u(n-1,x)+x*v(n-1,x)+1,

where u(1,x)=1, v(1,x)=1.

Example

First five rows:
1
2...3
2...8....9
2...10...30...27
2...10...46...108...81
First three polynomials v(n,x): 1, 2 + 3x , 2 + 8x + 9x^2.

Mathematica

u[1, x_] := 1; v[1, x_] := 1; z = 16;
u[n_, x_] := x*u[n - 1, x] + 2 x*v[n - 1, x] + 1;
v[n_, x_] := (x + 1)*u[n - 1, x] + 2 x*v[n - 1, x] + 1;
Table[Expand[u[n, x]], {n, 1, z/2}]
Table[Expand[v[n, x]], {n, 1, z/2}]
cu = Table[CoefficientList[u[n, x], x], {n, 1, z}];
TableForm[cu]
Flatten[%]    (* A209996 *)
Table[Expand[v[n, x]], {n, 1, z}]
cv = Table[CoefficientList[v[n, x], x], {n, 1, z}];
TableForm[cv]
Flatten[%]    (* A209998 *)

Crossrefs

Cf. A209996, A208510.

Sequence in context: A134347 A057761 A321477 * A349972 A163204 A364895

Adjacent sequences: A209995 A209996 A209997 * A209999 A210000 A210001

Keyword

nonn,tabl

Author

Clark Kimberling, Mar 23 2012

Extensions

a(55) corrected by Georg Fischer, Sep 03 2021

Status

approved