|
|
A205184
|
|
Period 12: repeat (1, 8, 4, 9, 7, 8, 7, 9, 4, 8, 1, 9).
|
|
0
|
|
|
1, 8, 4, 9, 7, 8, 7, 9, 4, 8, 1, 9, 1, 8, 4, 9, 7, 8, 7, 9, 4, 8, 1, 9, 1, 8, 4, 9, 7, 8, 7, 9, 4, 8, 1, 9, 1, 8, 4, 9, 7, 8, 7, 9, 4, 8, 1, 9, 1, 8, 4, 9, 7, 8, 7, 9, 4, 8, 1, 9, 1, 8, 4, 9, 7, 8, 7, 9, 4, 8, 1, 9, 1, 8, 4, 9, 7, 8, 7, 9, 4, 8, 1, 9, 1, 8
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,2
|
|
COMMENTS
|
The terms of this sequence are the digital roots of the indices of those nonzero triangular numbers that are also perfect squares (A001108).
|
|
LINKS
|
|
|
FORMULA
|
G.f.: x*(1+8*x+3*x^2+x^3+3*x^4-x^5+x^6+9*x^7) / ((1-x)*(1+x)*(1+x^2)*(1-sqrt(3)*x+x^2)*(1+sqrt(3)*x+x^2)).
a(n) = a(n-12).
a(n) = 25-a(n-1)-a(n-6)-a(n-7).
a(n) = a(n-2)-a(n-6)+a(n-8).
a(n) = 1/4*(25+(-1)^n*(9+4*sqrt(3)*(cos(n*Pi/6)-cos(5*n*Pi/6))+2*cos(n*Pi/2))).
|
|
EXAMPLE
|
As the fourth nonzero triangular number that is also a perfect square is A000217(288), and 288 has digital root A010888(288)=9, then a(4)=9.
|
|
MATHEMATICA
|
LinearRecurrence[{0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1}, {1, 8, 4, 9, 7, 8, 7, 9, 4, 8, 1, 9}, 86]
LinearRecurrence[{0, 1, 0, 0, 0, -1, 0, 1}, {1, 8, 4, 9, 7, 8, 7, 9}, 86] (* Ray Chandler, Aug 03 2015 *)
|
|
PROG
|
(PARI) a(n)=[9, 1, 8, 4, 9, 7, 8, 7, 9, 4, 8, 1][n%12+1] \\ Charles R Greathouse IV, Jul 17 2016
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn,easy
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|