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A187801
Pascal's triangle construction method applied to {1,1,2} as an initial term.
1
1, 1, 2, 1, 2, 3, 2, 1, 3, 5, 5, 2, 1, 4, 8, 10, 7, 2, 1, 5, 12, 18, 17, 9, 2, 1, 6, 17, 30, 35, 26, 11, 2, 1, 7, 23, 47, 65, 61, 37, 13, 2, 1, 8, 30, 70, 112, 126, 98, 50, 15, 2, 1, 9, 38, 100, 182, 238, 224, 148, 65, 17, 2, 1, 10, 47, 138, 282, 420, 462, 372
OFFSET
2,3
COMMENTS
A neighborhood decomposition of triangle graph applied to each node gives three identical sequences (independent of start point) {1,3}.
For star graph (depend of start point) generated sequences are: one time {1,3} and three times {1,1,2}.
Triangle of expansion of (1+x+2*x^2)*(1+x)^n. - Philippe Deléham, Mar 10 2013
LINKS
FORMULA
For the selection of the initial term: neighborhood decomposition of graph.
For sequence: Pascal's triangle construction method applied to selected initial term.
Row sums: A000079(n+2) = (4, 8, 16, 32, 64, ...). - Philippe Deléham, Mar 10 2013
EXAMPLE
Triangle begins:
1,1,2;
1,2,3,2;
1,3,5,5,2;
1,4,8,10,7,2;
1,5,12,18,17,9,2;
1,6,17,30,35,26,11,2;
1,7,23,47,65,61,37,13,2;
1,8,30,70,112,126,98,50,15,2;
1,9,38,100,182,238,224,148,65,17,2;
1,10,47,138,282,420,462,372,213,82,19,2;
1,11,57,185,420,702,882,834,585,295,101,21,2;
1,12,68,242,605,1122,1584,1716,1419,880,396,122,23,2;
1,13,80,310,847,1727,2706,3300,3135,2299,1276,518,145,25,2;
From Philippe Deléham, Mar 10 2013: (Start)
Row 2: 1+x+2*x^2
Row 3: (1+x+2*x^2)*(1+x) = 1+2*x+3*x^2+2*x^3
Row 4: (1+x+2*x^2)*(1+x)^2 = 1+3*x+5*x^2+5*x^3+2*x^4
Row 5: (1+x+2*x^2)*(1+x)^3 = 1+4*x+8*x^2+10*x^3+7*x^4+2*x^5
(End)
MATHEMATICA
c = {1, 1, 2}; Join[{c}, t = Table[c = Append[c, 0]; c = c + RotateRight[c], {9}]]; Flatten[t] (* T. D. Noe, Mar 11 2013 *)
CROSSREFS
KEYWORD
nonn,tabf
AUTHOR
STATUS
approved