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A183133
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Number of steps to compute the n-th prime in PRIMEGAME using Kilminster's Fractran program with only nine fractions.
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4
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10, 46, 196, 500, 1428, 2488, 4588, 6840, 10546, 17118, 23064, 33332, 44472, 55848, 70330, 90836, 115136, 137912, 168802, 201000, 233542, 276680, 320332, 373198, 439722, 503810, 568334, 640092, 712314, 792186, 917090, 1023878, 1146632, 1263818, 1419298
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OFFSET
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1,1
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REFERENCES
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D. Olivastro, Ancient Puzzles. Bantam Books, NY, 1993, p. 21.
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LINKS
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Eric Weisstein's World of Mathematics, FRACTRAN.
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MAPLE
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a:= proc(n) option remember;
local l, p, m, k;
l:= [3/11, 847/45, 143/6, 7/3, 10/91, 3/7, 36/325, 1/2, 36/5]:
if n=1 then b(0):= 10; a(0):= 0
else a(n-1)
fi;
p:= b(n-1);
for m do
for k while not type(p*l[k], integer)
do od; p:= p*l[k];
if 10^ilog10(p)=p then break fi
od:
b(n):= p;
m + a(n-1)
end:
seq(a(n), n=1..20);
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MATHEMATICA
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a[n_] := a[n] = Module[{l, p, m, k},
l = {3/11, 847/45, 143/6, 7/3, 10/91, 3/7, 36/325, 1/2, 36/5};
If[n == 1, b[0] = 10; a[0] = 0, a[n - 1]]; p = b[n - 1];
For[m = 1, True, m++,
For[k = 1, !IntegerQ[p*l[[k]]], k++];
p = p*l[[k]]; If[10^(Length@IntegerDigits[p]-1) == p, Break[]]];
b[n] = p; m + a[n - 1]];
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CROSSREFS
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KEYWORD
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easy,nonn
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AUTHOR
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STATUS
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approved
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