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A141066
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List of different composites in Pascal-like triangles with index of asymmetry y = 2 and index of obliquity z = 0 or z = 1.
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17
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4, 8, 9, 15, 28, 40, 52, 96, 88, 170, 177, 188, 326, 345, 189, 400, 600, 694, 406, 846, 1104, 1386, 871, 1779, 2031, 2751, 872, 1866, 3736, 6872, 7730, 10672, 4022, 8505, 12640, 15979, 20885, 4023, 8633, 18079, 23249, 32859, 40724, 42762, 67240, 18559, 39677, 78652, 80866, 153402
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OFFSET
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1,1
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COMMENTS
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For the Pascal-like triangle G(n, k) with index of asymmetry y = 2 and index of obliqueness z = 0, which is read by rows, we have G(n, 0) = G(n+1, n+1) = 1, G(n+2, n+1) = 2, G(n+3, n+1) = 4, G(n+4, k) = G(n+1, k-1) + G(n+1, k) + G(n+2, k) + G(n+3, k) for k = 1..(n+1). (This is array A140997.)
For the Pascal-like triangle with index of asymmetry y = 1 and index of obliqueness z = 1, which is read by rows, we have G(n, n) = G(n+1, 0) = 1, G(n+2, 1) = 2, G(n+3, 2) = 4, G(n+4, k) = G(n+1, k-2) + G(n+1, k-3) + G(n+2, k-2) + G(n+3, k-1) for k = 3..(n+3). (This is array A140994.)
The two triangular arrays A140997 and A140994, which are described above, are mirror images of each other.
To make the current sequence uniquely defined, we follow the suggestion of R. J. Mathar for sequence A141064. For each row of array A140997, the composites not appearing in earlier rows are collected, sorted, and added to the sequence. We get exactly the same sequence by working with array A140994 instead.
Finally, we mention that in the attached picture about the connection between Stepan's triangles and the Pascal triangle, the letter s is used to describe the index of asymmetry and the letter e is used to describe the index of obliqueness (instead of the letters y and z, respectively). The Pascal triangle A007318 has index of asymmetry s = y = 0 (and it does not matter whether we use e = 0 or e = 1 in the general formulas in the attached photograph).
(End)
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LINKS
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EXAMPLE
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Pascal-like triangle with y = 2 and z = 0 (i.e., A140997) begins as follows:
1, so no composite.
1 1, so no composite.
1 2 1, so no composite.
1 4 2 1, so a(1) = 4.
1 8 4 2 1, so a(2) = 8.
1 15 9 4 2 1, so a(3) = 9 and a(4) = 15.
1 28 19 9 4 2 1, so a(5) = 28.
1 52 40 19 9 4 2 1, so a(6) = 40 and a(7) = 52.
1 96 83 41 19 9 4 2 1, so a(8) = 96.
1 177 170 88 41 19 9 4 2 1, so a(9) = 88, a(10) = 170, and a(11) = 177.
1 326 345 188 88 41 19 9 4 2 1, so a(12) = 188, a(13) = 326, and a(14) = 345.
1 600 694 400 189 88 41 19 9 4 2 1, so a(15) = 189, a(16) = 400, a(17) = 600, and a(18) = 694.
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MAPLE
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# Construction of array A140997 (y = 2 and z = 0):
A140997 := proc(n, k) option remember; if k < 0 or n < k then 0; elif k = 0 or k = n then 1; elif k = n - 1 then 2; elif k = n - 2 then 4; else procname(n - 1, k) + procname(n - 2, k) + procname(n - 3, k) + procname(n - 3, k - 1); end if; end proc;
# Construction of the current sequence:
A141066 := proc(nmax) local a, b, n, k, new; a := []; for n from 0 to nmax do b := []; for k from 0 to n do new := A140997(n, k); if not (new = 1 or isprime(new) or new in a or new in b) then b := [op(b), new]; end if; end do; a := [op(a), op(sort(b))]; end do; RETURN(a); end proc;
# Generation of numbers in the current sequence:
# If one wishes to sort the numbers, then replace RETURN(a) with RETURN(sort(a)) in the above Maple code. In this case, however, the sequence is not uniquely defined because it depends on the maximum n. - Petros Hadjicostas, Jun 15 2019
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CROSSREFS
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Cf. A007318 (y = 0), A140993 (y = 1 and z = 1), A140994 (y = 2 and z = 1), A140995 (y = 3 and z = 1), A140996 (y = 3 and z = 0), A140997 (y = 2 and z = 0), A140998 (y = 1 and z = 0), A141020 (y = 4 and z = 0), A141021 (y = 4 and z = 1), A141064 (has primes when y = 1), A141065 (has composites when y = 1), A141067 (has primes when y = 2), A141068 (has primes when y = 3), A141069 (has composites when y = 3).
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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