|
|
A139777
|
|
Average of twin primes p4 = p1^3 + p2^2 such that p1 < p2 are consecutive primes and p3 = p1^2 + p2^3 is also an average of twin primes.
|
|
4
|
|
|
13008, 9268057799643918, 1151303780719281840798, 1166398496059056623580, 1408815704665167877050, 1611023943160530038112, 1839284737645145603808, 1876391173984974899670, 2541672151459722294708, 3760269231809150191932, 13232137801909374644760, 19086525662779517405622
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,1
|
|
LINKS
|
|
|
EXAMPLE
|
13008 = 23^3 + 29^2 is a term since 23 and 29 are consecutive primes, (13007, 13009) are twin primes, 23^2 + 29^3 = 24918, and (24917, 24919) are also twin primes.
|
|
MATHEMATICA
|
a={}; Do[p1=Prime[n]; p2=Prime[n+1]; p3=p1^2+p2^3; p4=p1^3+p2^2; If[PrimeQ[p3-1]&&PrimeQ[p3+1]&&PrimeQ[p4-1]&&PrimeQ[p4+1], AppendTo[a, p4]], {n, 13^5}]; Print[a];
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
|
|
EXTENSIONS
|
|
|
STATUS
|
approved
|
|
|
|