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A138762
Average of twin primes k such that k = p1^3 + p2^2, where p1 and p2 are consecutive primes, and p1 < p2.
0
13008, 8861225070, 13000005000, 38318210940, 51451234488, 64352692512, 68484878220
OFFSET
1,1
EXAMPLE
Numbers 13007 and 13009 are twin primes. Their average 13008 equals 23^3 + 29^2, where 23 and 29 are consecutive primes. Thus, 13008 is in this sequence. - Tanya Khovanova, Jul 21 2021
MATHEMATICA
a={}; Do[p1=Prime[n]; p2=Prime[n+1]; pp=p1^3+p2^2; If[PrimeQ[pp-1]&&PrimeQ[pp+1], AppendTo[a, pp]], {n, 16^3}]; Print[a];
CROSSREFS
Sequence in context: A190947 A203910 A354510 * A139777 A031633 A015327
KEYWORD
nonn,more
AUTHOR
STATUS
approved