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1, 2, 1, -1, 0, 1, 3, 2, 0, 1, -1, 0, 0, 0, 1, -2, -1, 2, 0, 0, 1, -1, 0, 0, 0, 0, 0, 1, 4, 3, 0, 2, 0, 0, 0, 1, 0, 0, -1, 0, 0, 0, 0, 0, 1, -2, -1, 0, 0, 2, 0, 0, 0, 0, 1, -1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, -3, -2, 3, -1, 0, 2, 0, 0, 0, 0, 0, 1, -1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1
(list;
table;
graph;
refs;
listen;
history;
text;
internal format)
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OFFSET
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1,2
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COMMENTS
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Row sums = A129502: (1, 3, 0, 6, 0, 0, 0, 10, 0, 0, ...).
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LINKS
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FORMULA
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EXAMPLE
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First few rows of the triangle are:
1;
2, 1;
-1, 0, 1;
3, 2, 0, 1;
-1, 0, 0, 0, 1;
-2, -1, 2, 0, 0, 1;
-1, 0, 0, 0, 0, 0, 1;
4, 3, 0, 2, 0, 0, 0, 1;
0, 0, -1, 0, 0, 0, 0, 0, 1;
...
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MATHEMATICA
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b[n_] := Module[{e}, Sum[e = IntegerExponent[d, 2]; If[d == 2^e, MoebiusMu[n/d] Binomial[2 + e, 2], 0], {d, Divisors[n]}]];
T[n_, k_] := If[Divisible[n, k], b[n/k], 0];
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PROG
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(PARI) T(n, k)={ if(n%k, 0, sumdiv(n/k, d, my(e=valuation(d, 2)); if(d==1<<e, moebius(n/(k*d))*binomial(2+e, 2), 0))) } \\ Andrew Howroyd, Aug 03 2018
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CROSSREFS
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KEYWORD
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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