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 A144409 Antidiagonal expansion of: f(t,n) = If[n == 1, 1/(1 - t), 1/(1 - t^floor(n/2) - t^n)]. 0
 1, 1, 1, 1, 1, 1, 1, 1, 2, 1, 1, 0, 1, 3, 1, 1, 0, 1, 2, 5, 1, 1, 0, 1, 0, 3, 8, 1, 1, 0, 0, 0, 2, 4, 13, 1, 1, 0, 0, 1, 1, 0, 6, 21, 1, 1, 0, 0, 1, 0, 1, 3, 9, 34, 1, 1, 0, 0, 0, 0, 0, 1, 0, 13, 55, 1, 1, 0, 0, 0, 1, 0, 2, 2, 5, 19, 89, 1, 1, 0, 0, 0, 1, 0, 1, 0, 1, 0, 28, 144, 1, 1, 0, 0, 0, 0, 0, 0, 1, 0, 3 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,9 COMMENTS Row sums are {1, 2, 3, 5, 6, 10, 14, 21, 31, 50, 71, 120, 177, 288, 445}. LINKS FORMULA f(t,n) = If[n == 1, 1/(1 - t), 1/(1 - t^floor(n/2) - t^n)); t(n,m) = antidiagonal_expansion(f(t,n)). EXAMPLE {1}, {1, 1}, {1, 1, 1}, {1, 1, 2, 1}, {1, 0, 1, 3, 1}, {1, 0, 1, 2, 5, 1}, {1, 0, 1, 0, 3, 8, 1}, {1, 0, 0, 0, 2, 4, 13, 1}, {1, 0, 0, 1, 1, 0, 6, 21, 1}, {1, 0, 0, 1, 0, 1, 3, 9, 34, 1}, {1, 0, 0, 0, 0, 0, 1, 0, 13, 55, 1}, {1, 0, 0, 0, 1, 0, 2, 2, 5, 19, 89, 1}, {1, 0, 0, 0, 1, 0, 1, 0, 1, 0, 28, 144, 1}, {1, 0, 0, 0, 0, 0, 0, 1, 0, 3, 8, 41, 233, 1}, {1, 0, 0, 0, 0, 1, 0, 0, 0, 3, 2, 0, 60, 377, 1} MATHEMATICA f[t_, n_] = If[n == 1, 1/(1 - t), 1/(1 - t^Floor[n/2] - t^n)]; a = Table[Table[SeriesCoefficient[Series[f[t, m], {t, 0, 30}], n], {n, 0, 30}], {m, 1, 31}]; b = Table[Table[a[[n - m + 1]][[m]], {m, 1, n }], {n, 1, 15}] ; Flatten[b] CROSSREFS Cf. A099238. Sequence in context: A027052 A322508 A194438 * A131257 A105806 A129501 Adjacent sequences:  A144406 A144407 A144408 * A144410 A144411 A144412 KEYWORD nonn,uned AUTHOR Roger L. Bagula and Gary W. Adamson, Sep 30 2008 STATUS approved

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Last modified September 16 10:23 EDT 2019. Contains 327094 sequences. (Running on oeis4.)